3 years ago

Evaluate the factorial expression. left parenthesis 6 minus 2 right parenthesis exclamation mark

1 answer:

4 0

If I understood your post correctly, then this will be the equation we evaluate: (6-2)!

We can simplify this to: 4!

4! = 4 x 3 x 2 x 1 = 24

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PlEASE HELP ME PEOPLE HUMPTH OK ILL SAY IT PEOPLE WANT MONEY TO ANSWER PROBLEMS HERE If the mean of six nu m b e rs is 48, does

SpyIntel [72]

Answer:

No, none of the number need to be 48 for the mean to be 48. To get a mean, you add up all the number and divide it by the amount of numbers.

Example:

the mean of 10, 79, 42, 88, 19, and 50 is 48, but the actual number 48 was not part of the set.

10 + 79 + 42 + 88 + 19 + 50 = 288

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2 years ago

(ab^2 x -b^4a^3)^2<br><br> What is the answers

Umnica [9.8K]

Answer:

$\left(ab^2x-b^4a^3\right)^2:\quad a^2b^4x^2-2a^4b^6x+a^6b^8$

Step-by-step explanation:

Given the expression

$\left(ab^2\:x\:-b^4a^3\right)^2$

solving the expression

$\left(ab^2\:x\:-b^4a^3\right)^2$

$\mathrm{Apply\:Perfect\:Square\:Formula}:\quad \left(a-b\right)^2=a^2-2ab+b^2$

$a=ab^2x,\:\:b=b^4a^3$

so the expression becomes

$=\left(ab^2x\right)^2-2ab^2xb^4a^3+\left(b^4a^3\right)^2$

$=a^2b^4x^2-2a^4b^6x+a^6b^8$

Thus,

$\left(ab^2x-b^4a^3\right)^2:\quad a^2b^4x^2-2a^4b^6x+a^6b^8$

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2 years ago

Anita says ray CD can also be called ray dc. do you agree?

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2 years ago

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Based on my calculation i know for sure F
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2 years ago

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5. I, II, III, IV, V,<br> Conjecture:

NemiM [27]

The conjecture is each term is the corresponding Roman numeral of the precious term

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3 years ago