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Oliga [24]
3 years ago
7

You are getting a line-up ready for a school kickball game. You have

Mathematics
1 answer:
damaskus [11]3 years ago
3 0
There are 28,800 ways.

There are 10 possibilities for the first child, since it could be a boy first or a girl first.  After this, there are 5 possibilities for the second child (the other gender).  There are 4 choices for the 3rd child, 4 for the 4th child, 3 for the 5th child, 3 for the 6th child, 2 for the 7th child, 2 for the 8th child, 1 for the 9th child, and 1 for the 10th child:
10(5)(4)(4)(3)(3)(2)(2)(1)(1) = 28,800
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8 0
2 years ago
Rob is twice Joshua's age. Nick is 5 years older than Joshua. The sum of all their ages is 45. How old is Nick?
MatroZZZ [7]

Given

Rob is twice Joshua's age

Nick is 5 years older than Joshua.

sum of all their ages is 45.

Find the age of nick.

To proof

As given

Rob is twice Joshua's age

let  Joshua's age = x

than Rob age = 2x

Nick is 5 years older than Joshua.

Nick age = 5 + x

sum of all their ages is 45

than the equation becomes

Joshua's age + Rob age + Nick age = 45

put the value

x + 2x + 5 + x = 45

4x = 40

x = 10

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Hence proved


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