Answer:
Length = 2w
Width= w
2w times w= 241
2W^2=241
Divide by 2
W-^2=121
Sq rt each side
W-= 11 cuz 11 times 11=121
hope this helped
If it did, brainliest would be appreciated!
Answer:
C
Step-by-step explanation:
There has to be two variables it's being compared to, in which case this is the blood sugar level and the amount of sugar
Answer:
13
Step-by-step explanation:
Since we want to find f(x) when x equals 10, we can substitute 10 in for x
f(x)=x/2 +8
f(10)=10/2+8
Divide 10 by 2
f(10)=5+8
Add 5 and 8
f(10)=13
So, f(x) when x=10 is 13
Answer:
20s=m
Step-by-step explanation:
I really don't understand it that well but all that I can is that s can represent students that went on the trip, and each student's ticket cost is 20$, so 20*s=20s, but we are taking m as the total money collected, so we can end up saying that 20s=m, hope u understood :)
Answer:
maximum height is 4.058 metres
Time in air = 0.033 second
Step-by-step explanation:
Given that the equation height h
h = -212t^2 + 7t + 4
What is the toy's maximum height?
Let us assume that the equation is a perfect parabola
Time t at Maximum height will be
t = -b/2a
Where b = 7 and a = - 212
t = -7/ - 212 ×2
t = 7/ 424 = 0.0165s
Substitute t in the main equation
h = - 212(7/424)^2 + 7(7/424) + 4
h = - 0.05778 + 0.115567 + 4
h = 4.058 metres
Therefore the maximum height is 4.058 metres
How long is the toy in the air?
The object will go up and return to the ground.
At ground level, h = 0
-212t^2 + 7t + 4 = 0
212t^2 - 7t - 4 = 0
You can factorize the above equation and pick the positive time t since time can't be negative
Or
Since we have assumed that it's a perfect parabola,
Total time in air = (-b/2a) × 2
Time in air = 0.0165 × 2 = 0.033 s
