Answer:
27 chickens
Step-by-step explanation:
A chicken farmer also has cows for a total of 30 animals
Both animals have a total of 66 legs
Let a represent the number of chicken
Let b represent the number of cows
a + b= 30........equation 1
Since a chicken has only two legs and a cow has four leg then, the expression can be represented as
2a + 4b= 66........equation 2
From equation 1
a + b= 30
a = 30-b
Substitute 30-b for a in equation 2
2a + 4b= 66
2(30-b) + 4b= 66
60 - 2b + 4b= 66
60 + 2b= 66
2b= 66-60
2b= 6
b= 6/2
b= 3
Substitute 3 for b in equation 1
a + b = 30
a + 3=30
a= 30-3
a= 27
Hence the farmer has 27 chickens
M=-2+-4
———=2/1=1
4 + -3
(4,3 ), (-2,-4)
(X1,y1)(x2,y2)
Answer:
yes
Step-by-step explanation:
The cost function is
c = 0.000015x² - 0.03x + 35
where x = number of tires.
To find the value of x that minimizes cost, the derivative of c with respect to x should be zero. Therefore
0.000015*2x - 0.03 = 0
0.00003x = 0.03
x = 1000
Note:
The second derivative of c with respect to x is positive (= 0.00003), so the value for x will yield the minimum value.
The minimum cost is
Cmin = 0.000015*1000² - 0.03*1000 + 35
= 20
Answer:
Number of tires = 1000
Minimum cost = 20
