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2 years ago

6

The distance across a two lane road

1 answer:

Vladimir79 [104]2 years ago

3 0

<u><em>In the United States, the Interstate Highway standards for the Interstate Highway System use a 12 ft (3.7 m) standard lane width, while narrower lanes are used on lower classification roads. In Europe, laws and road widths vary by country; the minimum widths of lanes are generally between 2.5 to 3.25 m (98 to 128 in).</em></u>

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What is the total number of common tangents that can be drawn to the circles

Alexxx [7]

The total number of common tangents that can be drawn to the circles is 2.

<h3>What is a tangent?</h3>

A tangent serves as line that touches the circle at a single point whereby the point where tangent meets the circle is the tangency.

A tangent to a circle can be described as the straight line that touches the circle at only one point.

Therefore, from the definition, The total number of common tangents that can be drawn to the circles is 2.

Read more on the tangent here:

brainly.com/question/12926708

#SPJ1

6 0

1 year ago

Write 0.000073 in scientific notation

Llana [10]

Answer:

7.3x10^-7

Step-by-step explanation:

you move the decimal to the right 7 times.

Hope this helps.

7 0

3 years ago

Read 2 more answers

818 divided by 34 in standard althriam

zalisa [80]

818 divided by 34 is 24.0588235. hope this helps!!

6 0

2 years ago

If the area of a sector is 100 ft^2 and the radius of the circle is 22 ft what is the central angle measure for that sector and

ahrayia [7]

Answer:

$\displaystyle \theta=0.413\ rad$

<em>L= 9.086 feet</em>

Step-by-step explanation:

<u>Area of a Circular Sector</u>

Given a circle of radius r, the area of a circular sector defined by a central angle θ (in radians) is given by

$\displaystyle A=\frac{1}{2}r^2\theta$

And the length of the arc is:

$L=\theta r$

We know the area of the sector is 100 square feet and the radius is r=33 ft, thus:

$\displaystyle 100=\frac{1}{2}r^2\theta$

Solving for θ:

$\displaystyle \theta=\frac{200}{r^2}$

$\displaystyle \theta=\frac{200}{22^2}$

$\displaystyle \theta=0.413\ rad$

The arc length is:

$L=0.413* 22$

L= 9.086 feet

6 0

3 years ago

Angel and jayden where in track practice . the track is 2/5 kilometers around.

Luden [163]

Distance equals velocity times time.

d=vt

v=d/t

v=(3*2/5)km/5min

v=(6/5)/5

v=6/25 km/min

v=0.24 km/min

3 0

3 years ago