Answer:
1 is the answer to your question mate
Answer:
$0.60
Step-by-step explanation:
Answer:
The population for the first year is 75.35.
Step-by-step explanation:
Solution:
Given Data;
Carrying capacity (K) = 100
Growth rate (r) = 1.8% = 0.018
Initial population (Po) = 75
time = first year
Population at any given time (pt) = ?
Using the population growth rate formula, we have
<h2>
dp/dt = rp (1-p/t)---------------------------1</h2>
Where r is the growth rate, t is the given time and p is the population growth
Equation 1 is differentiated and is obtained as;
<h2>Pt = K/ [1 + (K-Po/Po)e^-rt]------------2</h2>
Substituting into equation 2, we have
Pt = 100/[ 1+ (100-75/75) *e^-0.018*1]
Pt = 100/[1+ (0.333 * e^-0.018]
= 100/[1 +(0.333*0.982)]
= 100/[1 + 0.327]
= 100/1.327
=75.35
The trapeze area is:
A = (1/2) * (B + b) * (h)
Where,
B: major base
b: minor base
h: height
Substituting values:
A = (1/2) * (8.5 + 4) * (2)
A = 12.5 feet ^ 2
For two gallons of paint the number of trapezoids is:
N = (2 * 350) / (12.5)
N = 56
Answer:
Lillian can paint with 2 gallons of paint 56 front frames of a podium
Answer:
D
Step-by-step explanation:
Solve each inequality separately
- 8x + 44 ≥ 60 ( subtract 44 from both sides )
- 8x ≥ 16
Divide both sides by - 8, reversing the sign as a consequence
x ≤ - 2
and
- 4x + 50 < 58 ( subtract 50 from both sides )
- 4x < 8
Divide both sides by - 4, reversing the sign as a consequence
x > - 2
x cannot be less than or equal to 2 and greater than 2 , thus
there is no solution → D
