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Anna35 [415]
3 years ago
13

How do you solve this problem using substitution and then check it?:y= -3x-2 2x+5y=16

Mathematics
2 answers:
IrinaVladis [17]3 years ago
8 0
We have the variable y so lets substitute
y=-3x-2
2x+5y=16

2x+5y=16
2x+5(-3x-2)=16
2x-15x-10=16
-13x=26
x=-2

y=-3x-2
  =-3(-2)-2
  =4

2x+5y=16
2(-2)+5(4)=16
-4+20=16
16=16
VashaNatasha [74]3 years ago
4 0
You have to get a variable by itself like in here... Y is itself so in the other equation or we can say second one you just have to sub it in... Like

2x+5(-3x-2)=16
2x-15x-10=16
Now you just have to subtract 2 from 15, because of the same variable that is (x)
So -13x-10=16
Take 10 to the other side means add from the both sides, that will get you at
-13x=26
So now x= -2
Remember you added because it was -10 if it would be a positive 10 then you have to subtract it from both of the sides but since here it was negative so you just added them up
Hope i helped
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Answer:

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Step-by-step explanation:

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∵ h = -16t² + 320

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∴ 0 = -16t² + 320 ⇒ add 16t² to both sides

∴ 16t² = 320 ⇒ divide both sides by 16

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