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Anna35 [415]
3 years ago
13

How do you solve this problem using substitution and then check it?:y= -3x-2 2x+5y=16

Mathematics
2 answers:
IrinaVladis [17]3 years ago
8 0
We have the variable y so lets substitute
y=-3x-2
2x+5y=16

2x+5y=16
2x+5(-3x-2)=16
2x-15x-10=16
-13x=26
x=-2

y=-3x-2
  =-3(-2)-2
  =4

2x+5y=16
2(-2)+5(4)=16
-4+20=16
16=16
VashaNatasha [74]3 years ago
4 0
You have to get a variable by itself like in here... Y is itself so in the other equation or we can say second one you just have to sub it in... Like

2x+5(-3x-2)=16
2x-15x-10=16
Now you just have to subtract 2 from 15, because of the same variable that is (x)
So -13x-10=16
Take 10 to the other side means add from the both sides, that will get you at
-13x=26
So now x= -2
Remember you added because it was -10 if it would be a positive 10 then you have to subtract it from both of the sides but since here it was negative so you just added them up
Hope i helped
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What is the answer cos75 degrees=10/x
vova2212 [387]
To find the answer we simply work out the equation.
cos (75) = 10/x

cos (75) * x = 10. Here, I simply multiplied both sides by x to move x to the left hand side of the equation.

x = 10 / cos (75) Here, I divided cos (75) on both sides to move cos (75) to the right hand side of the equation.

The cosine of 75 is 0.92175127, so, 10 / 0.92175127 = 10.8489137
4 0
3 years ago
Write a formula for a Riemann sum for the function f (x )equals 1089 minus x squared over the interval ​[0,33​].
Mashcka [7]

Answer:

Area of 23958

Step-by-step explanation:

The Riemann sum is just the divide of a area into smaller areas and computing the sum of those areas. It is basically the integral of a function over an interval.

\int\limits {1089-x^2} \, dx

over the interval [0,33].

\int\limits {1089-x^2} \, dx=1089x-(x^3)/3

evaluate

=0-1089\cdot{33}-(33^3)/3=35937-11979=23958

4 0
3 years ago
What is the area of the shaded region?<br> 21 m<br> 23 m<br> 10 m<br> 34 m
Alina [70]

Answer:

572

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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AVprozaik [17]

Answer:

A reflection over the <em>y</em>-axis.

8 0
3 years ago
Write an equation to model growth or decay in the following scenario. A stock is declining at a rate of 25% of its value every 2
yawa3891 [41]

The exponential function that models this situation is:

y(t) = 225(0.75)^{\frac{t}{2}}

------------------------------------------

A decaying exponential function has the following format:

y(t) = y(0)(1 - r)^t

In which:

  • y(0) is the initial value.
  • r is the decay rate, as a decimal.

In this problem:

  • The stock started at $225, thus y(0) = 225.
  • Declines at a rate of 25% every 2 weeks, thus r = 0.25, t = \frac{t}{2}

The equation is:

y(t) = y(0)(1 - r)^t

y(t) = 225(1 - 0.25)^{\frac{t}{2}}

y(t) = 225(0.75)^{\frac{t}{2}}

A similar problem is given at brainly.com/question/24282972

3 0
3 years ago
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