Question

If f(x) = x^2/x+3, find f(x+h)

Answer 1

Answer:

Step-by-step explanation:

You just need to replace all the x's in the equation with (x+h).

So (x+h)^2/(x+h)+3.

I can't tell from the original, but if it is ((x+h)^2) / ((x+h)+3), (over the complete thing) then it can't be simplified and that is the answer.

But if it is ((x+h)^2)/(x+h) + 3, then you can cancel one of the (x+h)'s on the top and get (x+h) + 3 overall.

Answer 2

Answer:

$f(x+h)=\frac{x^2+2xh+h^2}{x+h+3}$ is the answer

given the function $f(x)=\frac{x^2}{x+3}$.

Step-by-step explanation:

$f(x)=\frac{x^2}{x+3}$ is the given function.

I'm going to do some examples of plugging in because that is what this problem is asking you to do.

Example 1: What is f(2)?

f(2) means we are going to replace x with 2 in the thing we called f:

$f(2)=\frac{2^2}{2+3}$

$f(2)=\frac{4}{5}$

Example 2: What is f(-2)?

f(-2) means we are going to replace x with -2 in the thing we called f.  Before we do this I just wanted to tell you something here about negative numbers or expressions.  When plugging in either of these, use ( ) around the number you are plugging in. So I should re-say my first line here.  

f(-2) means we are going to replace x with (-2) in the thing we called f:

$f(-2)=\frac{(-2)^2}{(-2)+3}$

$f(-2)=\frac{4}{1}$

$f(-2)=4$.

Example 3: What is f(cat+tuna)?

f(cat+tuna) means we are going to replace x with (cat+tuna) in the thing we called f:

$f(\text{cat+tuna})=\frac{(\text{cat+tuna})^2}{(\text{cat+tuna})+3}$

$f(\text{cat+tuna})=\frac{(\text{cat+tuna})^2}{\text{cat+tuna}+3}$

To expand the top, we are going to use this formula for squaring a sum:

$(u+v)^2=u^2+2uv+v^2$.

$f(\text{cat+tuna})=\frac{(\text{cat})^2+2\cdot \text{cat} \cdot \text{tuna}+(\text{tuna})^2}{\text{cat+tuna}+3}$

Ok let's move on to the true problem:

f(x+h) means to replace x with (x+h) in the thing we called f:

$f(x+h)=\frac{(x+h)^2}{(x+h)+3}$

This is really the same problem we had above except without the cat and the tuna but with x and h respectively instead.

$f(x+h)=\frac{x^2+2xh+h^2}{x+h+3}$