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creativ13 [48]
2 years ago
8

Solve the following maximization problem graphically.

Mathematics
1 answer:
rjkz [21]2 years ago
6 0

The maximized value of the function is (c) 119/2

<h3>Maximization problem</h3>

Maximization problems are used to determine the optimal solution of a linear programming model

<h3>Objective function</h3>

The objective function is given as:

P(x,y) = 11x + 10y

<h3>Constraints</h3>

The constraints are given as:

22x + 2y \le 68

8x + 16y \le 68

x,y\ge 0

<h3>Graph</h3>

See attachment for the graph of the constraints

From the graph, the optimal solution is: (2.83, 2.83)

So, the maximized value is:

P(x,y) = 11x + 10y

P =11 \times 2.833 + 10 \times 2.833

P =59.493

Approximate

P =59.5

Rewrite as a fraction

P =\frac{119}{2}

Hence, the maximized value of the function is (c) 119/2

Read more about maximization problem at:

brainly.com/question/16826001

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Answer:

Shortest distance from A to C = 102.9005 m.

Step-by-step explanation:

It is given that, ABCD is a rectangular park.

The length of the park is 80 m.

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As one has to pass only through the lines shown, he cannot pass through the circle.

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One must pass through either half of the circumference of the circle.

Since, diameter of circle = 15 m, its radius(r) = \frac{15}{2} = 7.5 m.

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Distance from A to C passing through circumference = 79.339 m + 23.5615 m = 102.9005 m.

As we have to calculate the shortest distance from A to C, one cannot pass  from A to C either through B or D,

since the distance ABC or ADC = 50+80 = 130 m.

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0.09 is the only one smaller than 0.59

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