Let
x-------> the first number
y------> the second number
we know that
equation 
equation 
substitute equation 1 in equation 2
using a graph tool-----> to resolve the second order equation
see the attached figure
the solution is
3x² (6x² - 13x - 5) =
3x² (2x - 5) (2x+1) .
Answer:
<em>2 solutions</em>
Step-by-step explanation:
Given the expression
2m/2m+3 - 2m/2m-3 = 1
Find the LCM of the expression at the left hand side:
2m(2m-3)-2m(2m+3)/(2m+3)(2m-3) = 1
open the bracket
4m²-6m-4m²-6m/(4m²-9) = 1
Cross multiply
4m²-6m-4m²-6m = 4m² - 9
-12m = 4m² - 9
4m² - 9+12m = 0
4m² +12m-9 = 0
<em>Since the resulting equation is a quadratic equation, it will have 2 solutions since the degree of the equation is 2</em>
Answer: 54
Step-by-step explanation: I separated it into 3 areas in my head and then added up 21+21+12 to get 54
7 times 3 is 21
7 times 3 is 21
and
3 times 4 is 12
sorry if i am wrong i just did this in my head
