Can I get an example of systems of equations that represent the solution of this situation below? Thank you! ^ ^
1 answer:
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We know that
<span>the length of Q is 25% more than the length of p
</span>so
length Q=1.25*40--------> 50 cm
<span>the area of Q is 10% less than the area of p
Area Q=50*y
Area P=40*x
so
50*y=0.90*[40*x]---------> 50*y=36*x-------> x/y=50/36---> 25/18
the answer is
the ratio </span><span>x:y is
</span><span>25:18</span>
<span>the length of Q is 25% more than the length of p
</span>so
length Q=1.25*40--------> 50 cm
<span>the area of Q is 10% less than the area of p
Area Q=50*y
Area P=40*x
so
50*y=0.90*[40*x]---------> 50*y=36*x-------> x/y=50/36---> 25/18
the answer is
the ratio </span><span>x:y is
</span><span>25:18</span>