Answer: The hook would be 2.2 inches (approximately) above the top of the frame
Step-by-step explanation: Please refer to the picture attached for further details.
The top of the picture frame has been given as 9 inches and a 10 inch ribbon has been attached in order to hang it on a wall. The ribbon at the point of being hung up would be divided into 5 inches on either side (as shown in the picture). The line from the tip/hook down to the frame would divide the length of the frame into two equal lengths, that is 4.5 inches on either side of the hook. This would effectively give us two similar right angled triangles with sides 5 inches, 4.5 inches and a third side yet unknown. That third side is the distance from the hook to the top of the frame. The distance is calculated by using the Pythagoras theorem which states as follows;
AC^2 = AB^2 + BC^2
Where AC is the hypotenuse (longest side) and AB and BC are the other two sides
5^2 = 4.5^2 + BC^2
25 = 20.25 + BC^2
Subtract 20.25 from both sides of the equation
4.75 = BC^2
Add the square root sign to both sides of the equation
2.1794 = BC
Rounded up to the nearest tenth, the distance from the hook to the top of the frame will be 2.2 inches
Answer:
7c+18
Step-by-step explanation:
FIRST
take out the parentheses so it will be
( 1/3*9c)+12+4c+6
3c+12+4c+6
Combine like terms
a. Use the mean value theorem. 16 falls between 12 and 20, so
(Don't forget your units - 5 m/min^2)
b. 
gives the Johanna's velocity at time 
. The magnitude of her velocity, or speed, is 
. Integrating this would tell us the total distance she has traveled whilst jogging.
The Riemann sum approximates the integral as
If you're not sure how this is derived: we're given 5 sample points, so we can cut the interval [0, 40] into 4 subintervals. The lengths of each subinterval are 12, 8, 4, and 16 (the distances between each sample point), and the height of the rectangle approximating the area under the plot of is determined by the value of at each sample point, 200, 240, |-220| = 220, and 150.
c. Bob's velocity is given by 
, so his acceleration is given by 
. We have
and at 
his acceleration is 
m/min^2.
d. Bob's average velocity over [0, 10] is given by the difference quotient,
m/min
Answer:
D
Step-by-step explanation:
I usually use a z-score table, but you can do this with a calculator.
If we go to a z-score table, we first look up the first two digits (in this case, 2.8) in the far left column. Then we find the hundredths digit in the top row (0.07). Where they intersect is P(z < 2.87).
P(z < 2.87) = 0.9979
Answer D.
