All categories

2 years ago

Please help I just can’t find the answer

Mathematics

2 answers:

Talja [164]2 years ago

4 0

Answer:

Step-by-step explanation:

Mumz [18]2 years ago

4 0

Answer:

The arc-length of the semicircle is approximately 34.54 units

Step-by-step explanation:

Recall that the arc length of the whole circumference is defined by the formula:

$Circumference's \,\,length=2\,\pi\,R$

where R is the radius of the circle (in your case 11 units)

So the length of half a circumference (which is actually the arc length of the semicircle you are requested to find) would be half of the formula we just mentioned:

$Arc\,\,length=\pi\,R\\Arc\,\,length= 3.14\,(11)\\Arc\,\,length= 34.54\, \,units$

You might be interested in

Hi! Is there anyone good with finding the surface area of something? If so, please comment. If you do help me, I will give you 5

Aleks [24]

No sorry 123
God bless you

7 0

2 years ago

Distance on the Coordinate Plane

s344n2d4d5 [400]

9514 1404 393

Answer:

B. 10 units

Step-by-step explanation:

The distance formula is useful.

d = √((x2 -x1)² +(y2 -y1)²)

d = √((3-(-5))² +(-2-4)²) = √(64 +36) = √100

d = 10

The distance from L to M is 10 units.

6 0

2 years ago

Who can help me d e f thanks

12345 [234]

$y = (2ax^2 + c)^2 (bx^2 - cx)^{-1}$

Product rule:

$y' = \bigg((2ax^2+c)^2\bigg)' (bx^2-cx)^{-1} + (2ax^2+c)^2 \bigg((bx^2-cx)^{-1}\bigg)'$

Chain and power rules:

$y' = 2(2ax^2+c)\bigg(2ax^2+c\bigg)' (bx^2-cx)^{-1} - (2ax^2+c)^2 (bx^2-cx)^{-2} \bigg(bx^2-cx\bigg)'$

Power rule:

$y' = 2(2ax^2+c)(4ax) (bx^2-cx)^{-1} - (2ax^2+c)^2 (bx^2-cx)^{-2} (2bx - c)$

Now simplify.

$y' = \dfrac{8ax (2ax^2+c)}{bx^2 - cx} - \dfrac{(2ax^2+c)^2 (2bx-c)}{(bx^2-cx)^2}$

$y' = \dfrac{8ax (2ax^2+c) (bx^2 - cx) - (2ax^2+c)^2 (2bx-c)}{(bx^2-cx)^2}$

$y = \dfrac{3bx + ac}{\sqrt{ax}}$

Quotient rule:

$y' = \dfrac{\bigg(3bx+ac\bigg)' \sqrt{ax} - (3bx+ac) \bigg(\sqrt{ax}\bigg)'}{\left(\sqrt{ax}\right)^2}$

$y'= \dfrac{\bigg(3bx+ac\bigg)' \sqrt{ax} - (3bx+ac) \bigg(\sqrt{ax}\bigg)'}{ax}$

Power rule:

$y' = \dfrac{3b \sqrt{ax} - (3bx+ac) \left(-\frac12 \sqrt a \, x^{-1/2}\right)}{ax}$

Now simplify.

$y' = \dfrac{3b \sqrt a \, x^{1/2} + \frac{\sqrt a}2 (3bx+ac) x^{-1/2}}{ax}$

$y' = \dfrac{6bx + 3bx+ac}{2\sqrt a\, x^{3/2}}$

$y' = \dfrac{9bx+ac}{2\sqrt a\, x^{3/2}}$

$y = \sin^2(ax+b)$

Chain rule:

$y' = 2 \sin(ax+b) \bigg(\sin(ax+b)\bigg)'$

$y' = 2 \sin(ax+b) \cos(ax+b) \bigg(ax+b\bigg)'$

$y' = 2a \sin(ax+b) \cos(ax+b)$

We can further simplify this to

$y' = a \sin(2(ax+b))$

using the double angle identity for sine.

7 0

1 year ago

A clothing store sold three times as many shirts as pants. The difference in the sales was 800. How many of each were sold?

Salsk061 [2.6K]

Answer:

1200 shirts were sold.

400 pants were sold.

Step-by-step explanation:

The ratio of shirts to pants sold = 3:1 (difference of 2)

800 ÷ 2 = 400

Ratio x 400 = 1200:400 (difference of 800)

4 0

3 years ago

F(n+1)=f(n)-8. If f(1)=100,what Is f(6)

Tanya [424]

I think it is f(6)= 39

6 0

3 years ago