Complete the square:
<span>y = 3x^2 - 12x + 4 </span>
<span>y = 3(x^2 - 4x) + 4 </span>
<span>y = 3(x^2 - 4x + 4 - 4) + 4 </span>
<span>y = 3(x^2 - 4x + 4) - 12 + 4 </span>
<span>y = 3(x - 2)^2 - 8</span>
X^8 = ()^2
x^8 = (x^4)^2
x^8 = x^8
inside the parethesis is x^4
hope this helps
Answer:
(x + 5)^2 = (5 - 3)^2
Step-by-step explanation:
Given the equation;
x^2 + 10x + 22 = 13
We have;
x^2 + 10x = 13 - 22
x^2 + 10x = -9
Adding half of 10 to both sides and completing the square as usual, we have;
(x + 5)^2 = 5^2 + (-9)
(x + 5)^2 = (5 - 3)^2
I could only do b
3(2x + 4) = 2+6x+10
6x+12 = 2+6x+10
6x- 6x = 2+10-12
0x/0 = 0/0
x = 0
I think
