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EleoNora [17]
3 years ago
12

A line passes through the points (1, 6) and (0, 2). What is its equation in slope-intercept

Mathematics
1 answer:
lubasha [3.4K]3 years ago
8 0
The equation would be Y = 4x + 2
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Twice the sum of 13 and x is not greater than 15
Kobotan [32]

Answer:

x = 0

Step-by-step explanation:

This is saying that 2(13x) < 15

If you have 2[13(0)] < 15

It will come to 2(0) < 15

This equals 0 < 15 which is true therefore making the <u>x</u> value = <u>0</u>

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A rectangular pyramid. The rectangular base has a length of 10 inches and a width of 6 inches. 2 triangular sides have a base of
melisa1 [442]

Answer:

Answer:

a) The base of the rectangular pyramid shown has an area of

60 square inches

b) A triangular face with a base of 10 inches has an area of 28 square inches.

c) A triangular face with a base of 5 inches has an area of 17.75 square inches.

d) The total surface area of the pyramid is 151.5 square inches.

Step-by-step explanation:

a) Solving for question a, we were given the following parameters

A rectangular pyramid. The rectangular base has a length of 10 inches and a width of 6 inches

The formula used to calculate the rectangular base of a rectangular pyramid =

Length × Width

Where :

Length = 10 inches

Width = 6 inches

Rectangular base = 10 inches × 6 inches

= 60 inches²

Hence, the base of the rectangular pyramid shown has an area of 60 square inches

b) Solving for question b, we have the following values given:

2 triangular sides have a base of 10 inches and height of 5.6 inches.

First step would be to solve for one triangular side first.

The area of the one triangular side = (Base × Height) ÷ 2

= (10 inches × 5.6 inches) ÷ 2

= 56inches² ÷ 2

= 28 inches²

Therefore, for the 2 triangular sides, since they have the same base and height, the other side as well would be 28 inches².

A triangular face with a base of 10 inches has an area of 28 square inches.

c) Solving for question c, the following parameters are given:

2 triangular sides have a base of 5 inches and height of 7.1 inches.

We would be to solving for one triangular side first.

The area of the one triangular side = (Base × Height) ÷ 2

= (5 inches × 7.1 inches) ÷ 2

= 35.5 inches² ÷ 2

= 17.75 inches²

Therefore, for the 2 triangular sides, since they have the same base and height, the other side as well would be 17.75 inches².

A triangular face with a base of 5 inches has an area of 17.75 square inches.

d) Solving for d, it is important to note that, a rectangular pyramid has 5 faces and they are: The rectangular base and 4 triangular faces

The formula for the total surface area of the rectangular pyramid is given as

Total Surface Area of the rectangular pyramid = Rectangular Base + Area of Triangular Side A + Area of Triangular Side B + Area of Triangular Side C + Area of Triangular Side D + Area of Triangular Side E

Total Surface Area of the Rectangular Pyramid = 60 inches² + 28 inches² + 28 inches² + 17.75 inches² + 17.75 inches²

Total surface Area of the Rectangular pyramid = 151.5 inches²

The total surface area of the pyramid is 151.5 square inches.

Step-by-step explanation:

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3 years ago
A student is solving the equation 4^x–1 = 64^x+3.
Doss [256]
The answer is <span>x - 1 = 3x + 9

All steps are:
</span>Step 1: 4ˣ⁻¹ = 64ˣ⁺³<span> 
Step 2: 4</span>ˣ⁻¹ = (4³)ˣ⁺³ <span>
Step 3: 4</span>ˣ⁻¹ = 4³ˣ⁺⁹ 
Step 4: x - 1 = 3x + 9
Step 5: x - 3x = 1 + 9
Step 6: -2x = 10
Step 7: x = 10/-2
Step 8: x = -5
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