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pickupchik [31]

4 years ago

12

Now you will use what you have learned to create a general test for determining whether two functions are inverses. If f(x) and

g(x) are inverses, what will be the values of f(g(x)) and g(f(x))?

1 answer:

Ksju [112]4 years ago

6 0

The values of the 2 compound functions will be x.

For example if f(x) = x + 1 and g(x) = x - 1 then

f(g(x)) = (x - 1) + 1 = x

and g(f(x)) = x + 1 - 1 = x

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Bess [88]

Kites are quadrilaterals so other than a rhombus, it would be a square. A kite can also be shaped as a square.

hope it helps!

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3 years ago

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no one belongs to both math club and photography club, but the two clubs join to hold a car was. nine member of the math club an

stiv31 [10]

Since there are a total number of 15 members participating, you would divide 150 by 15 since everyone would get their fair share. Next you would multiply 10 by 9 which would result to $90 and the profit the math club received

4 0

3 years ago

Find all solutions <br> 36x²+12x=0

FromTheMoon [43]

Answer:

x = -1/3 or 0

Step-by-step explanation:

Given equation:

$36x^{2} + 12x = 0$

We can factor 12x on the L.H.S since 12x is divisible by 36x² and 12x.

$\implies 36x^{2} + 12x = 0$

$\implies 12x(3x + 1) = 0$

This can lead to two solutions. I have listed them below!

<h2>Solution 1:</h2>

Divide 12x on both sides to open the parentheses.

$\implies 12x(3x + 1) = 0$

$\implies \dfrac{12x(3x + 1)}{12} = \dfrac{0}{12}$

<em>Note: zero divided by any non-zero number is 0.</em>

$\implies \dfrac{12x(3x + 1)}{12} = \dfrac{0}{12}$

$\implies 3x + 1 = 0$

Isolate 3x on one side of the equation.

$\implies 3x + 1 = 0$

$\implies 3x = 0 - 1$

$\implies 3x = -1$

Divide 3 both sides to determine the value of x.

$\implies 3x = -1$

$\implies \dfrac{3x}{3} = \dfrac{-1}{3}$

$\implies \boxed{x = \dfrac{-1}{3}}$

<h2>Solution 2:</h2>

Divide (3x + 1) on both sides to isolate 12x.

$\implies 12x(3x + 1) = 0$

$\implies \dfrac{12x(3x + 1)}{(3x + 1)} = \dfrac{0}{(3x + 1)}$

<em>Note: zero divided by any non-zero number is 0.</em>

$\implies \dfrac{12x(3x + 1)}{(3x + 1)} = \dfrac{0}{(3x + 1)}$

$\implies 12x = 0$

Divide 12 both sides to determine the value of x.

$\implies 12x = 0$

$\implies \dfrac{12x}{12} = \dfrac{0}{12}$

$\implies \boxed{x = 0}$

Therefore, the solutions for x are -1/3 or 0.

Learn more about this topic: brainly.com/question/295675

5 0

2 years ago

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Simplify. 13(1−14)2 Enter your answer, as a simplified fraction, in the box.

babymother [125]

Answer.

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7 0

4 years ago

How you solve this??

nika2105 [10]

Step-by-step explanation:

so your answer will come

8 0

3 years ago