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1 year ago

Please create an example using exponential growth and exponential decay

Mathematics

1 answer:

inessss [21]1 year ago

4 0

Answer:

f(x)=4^x exponential growth, -6^x exponential decay Step-by-step explanation:

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Mike has a stack of 10 cards numbered 1 to 10 if he randomly chooses two cards without replacing the first one drawn what is the

Gekata [30.6K]

4 out of 10 because the amount of prime numbers from 1- 10 is

2, 3, 5, and 7.

Hope this helps!

7 0

2 years ago

Read 2 more answers

What number is less than 15.22 Enter your answer as a decimal in the box

Harlamova29_29 [7]

Answer:

15.10 or -15.22

Step-by-step explanation:

3 0

2 years ago

Is 12/35 less than 3/5

stepan [7]

Answer:

yes

Step-by-step explanation:

3/5 is closer to being a full number =D

7 0

2 years ago

Consider the following region R and the vector field F. a. Compute the two-dimensional curl of the vector field. b. Evaluate bo

Shalnov [3]

Looks like we're given

$\vec F(x,y)=\langle-x,-y\rangle$

which in three dimensions could be expressed as

$\vec F(x,y)=\langle-x,-y,0\rangle$

and this has curl

$\mathrm{curl}\vec F=\langle0_y-(-y)_z,-(0_x-(-x)_z),(-y)_x-(-x)_y\rangle=\langle0,0,0\rangle$

which confirms the two-dimensional curl is 0.

It also looks like the region $R$ is the disk $x^2+y^2\le5$ . Green's theorem says the integral of $\vec F$ along the boundary of $R$ is equal to the integral of the two-dimensional curl of $\vec F$ over the interior of $R$ :

$\displaystyle\int_{\partial R}\vec F\cdot\mathrm d\vec r=\iint_R\mathrm{curl}\vec F\,\mathrm dA$

which we know to be 0, since the curl itself is 0. To verify this, we can parameterize the boundary of $R$ by

$\vec r(t)=\langle\sqrt5\cos t,\sqrt5\sin t\rangle\implies\vec r'(t)=\langle-\sqrt5\sin t,\sqrt5\cos t\rangle$

$\implies\mathrm d\vec r=\vec r'(t)\,\mathrm dt=\sqrt5\langle-\sin t,\cos t\rangle\,\mathrm dt$

with $0\le t\le2\pi$ . Then

$\displaystyle\int_{\partial R}\vec F\cdot\mathrm d\vec r=\int_0^{2\pi}\langle-\sqrt5\cos t,-\sqrt5\sin t\rangle\cdot\langle-\sqrt5\sin t,\sqrt5\cos t\rangle\,\mathrm dt$

$=\displaystyle5\int_0^{2\pi}(\sin t\cos t-\sin t\cos t)\,\mathrm dt=0$

7 0

2 years ago

Can a trapezoid have congruent diagonals?

Maslowich

Answer:

Yes

Step-by-step explanation:

If the the trapezoid is Isosceles, meaning the legs, or the line segments connecting the bases are equal.

5 0

2 years ago