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pychu [463]
3 years ago
6

The volume of a cube is 130 cubic inches.write the length of a side of the cube as a irrational number. Approximate the length t

o the 2 decimal places
Mathematics
1 answer:
Elena-2011 [213]3 years ago
8 0

Answer:

5.07

Step-by-step explanation:

The volume of a cube is it's side length squared.

We can represent the side length as x.

x^3=130.

Then, taking the cubic root,

x=5.07

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In the figure, ∆ABC~∆XYZ. What is the perimeter of ∆ABC? Show your work.
Elina [12.6K]

Answer:

49 units

Step-by-step explanation:

Given the triangles are similar then the ratios of corresponding sides are equal, that is

\frac{BC}{YZ} = \frac{AB}{XY}, substitute values

\frac{BC}{44} = \frac{11}{22} ( cross- multiply )

22BC = 484 ( divide both sides by 22 )

BC = 22

------------------------------------------------

Similarly

\frac{AC}{XZ} = \frac{AB}{XY}, substitute values

\frac{AC}{32} = \frac{11}{22} ( cross- multiply )

22AC = 352 ( divide both sides by 22 )

AC = 16

Thus perimeter of Δ ABC is

perimeter = AB + BC + AC = 11 + 22 + 16 = 49 units

5 0
4 years ago
3. Peri earned $27 for walking her neighbor's dog 3 times. If pe the same rate and earned $36, how many times did she wall neigh
Andrei [34K]

Answer:

She walked neighbor's dog 4 times.

Step-by-step explanation:

It is given that:

Peri earned $27 for walking the dogs 3 times.

Unit rate = \frac{27}{3}

Unit rate = $9 per dog

Now,

Peri worked at the same rate and earned $36.

Unit rate = \frac{Total\ earning}{Dogs\ walked}

9 = \frac{36}{d}

d= 36/9

d = 4

Therefore,

She walked neighbor's dog 4 times.

7 0
3 years ago
Find the circumference of a circle if the area is 45m^2
ki77a [65]
C=2pir
A=pir^2
45=pir^2
divide both sides by pi (aprox pi=3.141592)
14.32394785=r^2
sqrt both sides
3.784699176=r
sub
C=2pir
C=(2)(pi)(3.784699176)
aprox pi=3.141592
C=23.779961311m
3 0
3 years ago
How many positive integers $n$ satisfy $127 \equiv 7 \pmod{n}$? $n=1$ is allowed.
Svetllana [295]
Naturally, any integer n larger than 127 will return 127\equiv127\mod n, and of course 127\equiv0\mod127, so we restrict the possible solutions to 1\le n.

Now,

127\equiv7\mod n

is the same as saying there exists some integer k such that

127=nk+7

We have

\implies 120=nk

which means that any n that satisfies the modular equivalence must be a divisor of 120, of which there are 16: \{1,2,3,4,5,6,8,10,12,15,20,24,30,40,60,120\}.

In the cases where the modulus is smaller than the remainder 7, we can see that the equivalence still holds. For instance,

127=21\cdot6+1\iff127\equiv1\equiv7\mod6

(If we're allowing n=1, then I see no reason we shouldn't also allow 2, 3, 4, 5, 6.)
5 0
4 years ago
What is the volume, in cubic centimeters, of a
ASHA 777 [7]

Answer:

3cm

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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