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Anastaziya [24]
3 years ago
9

The number of typing errors made by a typist has a Poisson distribution with an average of two errors per page. If more than two

errors appear on a given page, the typist must retype the whole page. What is the probability that a randomly selected page does not need to be retyped? (Round your answer to three decimal places.)
Mathematics
1 answer:
wlad13 [49]3 years ago
6 0

Answer: 0.6767

Step-by-step explanation:

Given : Mean =\lambda=2 errors  per page

Let X be the number of errors in a particular page.

The formula to calculate the Poisson distribution is given by :_

P(X=x)=\dfrac{e^{-\lambda}\lambda^x}{x!}

Now, the probability that a randomly selected page does not need to be retyped is given by :-

P(X\leq2)=P(0)+P(1)+P(2)\\\\=(\dfrac{e^{-2}2^0}{0!}+\dfrac{e^{-2}2^1}{1!}+\dfrac{e^{-2}2^2}{2!})\\\\=0.135335283237+0.270670566473+0.270670566473\\\\=0.676676416183\approx0.6767

Hence, the required probability :- 0.6767

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Advandia is a drug used to treat diabetes, but it may cause an increase in heart attacks among a population already susceptible.
sergiy2304 [10]

Answer:

a) The proportions are not form matched-pairs data.

b) The null hypothesis failed to be rejected.

There is  not enough evidence to support the claim that there is evidence of a significant increase in the proportion of people who suffer heart attacks when using Avandia compared to other treatments.

Step-by-step explanation:

a) Two data sets are "paired" when the following one-to-one relationship exists between values in the two data sets:

  • Each data set has the same number of data points.
  • Each data point in one data set is related to one, and only one, data point in the other data set.

None of this conditions apply in this case, so the proportions are not form matched-pairs data.

b) This is a hypothesis test for the difference between proportions.

The claim is that there is evidence to suggest that there is a significant increase in the proportion of people who suffer heart attacks when using Avandia compared to other treatments.

Then, the null and alternative hypothesis are:

H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2> 0

The significance level is 0.05.

The sample 1 (Avindia treatment), of size n1=1456 has a proportion of p1=0.0185.

p_1=X_1/n_1=27/1456=0.0185

The sample 2 (other treatment), of size n2=2895 has a proportion of p2=0.0142.

p_2=X_2/n_2=41/2895=0.0142

The difference between proportions is (p1-p2)=0.0044.

p_d=p_1-p_2=0.0185-0.0142=0.0044

The pooled proportion, needed to calculate the standard error, is:

p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{27+41}{1456+2895}=\dfrac{68}{4351}=0.0156

The estimated standard error of the difference between means is computed using the formula:

s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.0156*0.9844}{1456}+\dfrac{0.0156*0.9844}{2895}}\\\\\\s_{p1-p2}=\sqrt{0.00001+0.00001}=\sqrt{0.00002}=0.004

Then, we can calculate the z-statistic as:

z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{0.0044-0}{0.004}=\dfrac{0.0044}{0.004}=1.1

 

This test is a right-tailed test, so the P-value for this test is calculated as (using a z-table):

P-value=P(z>1.1)=0.1358

As the P-value (0.1358) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is  not enough evidence to support the claim that there is evidence to suggest that there is a significant increase in the proportion of people who suffer heart attacks when using Avandia compared to other treatments.

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Answer:

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Step-by-step explanation:

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