Solution:
Number of times a die is rolled = 20
1 - 3=A
2 - 5=B
3 - 4=C
4 - 2=D
5 - 3=E
6 - 3=F
Total number of arrangements of outcomes , when a dice is rolled 20 times given that 1 appear 3 times, 2 appears 5 times, 3 appear 4 times, 4 appear 2 times , 5 appear three times, and 6 appear 3 times
= Arrangement of 6 numbers (A,B,C,D,E,F) in 6! ways and then arranging outcomes
= 6! × [ 3! × 5! × 4!×2!×3!×3!]
= 720 × 6×120×24×72→→[Keep in Mind →n!= n (n-1)(n-2)(n-3)........1]
= 895795200 Ways
Answer:
Step-by-step explanation:
First, we open the parentheses by multiplying the contents of the parentheses by 3 (because it says 3(2x+6)). The final result is <u>6x+18</u>
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Step-by-step explanation:
Answer:
The notation p ∧ q represents the statement “The book is interesting
✔ and <-- Answer
the book has pictures.”
The notation p ↔ q represents the statement “The book is interesting
✔ if and only if <-- Answer
the book has pictures.”
The notation q ∨ p represents the statement “The book has pictures
✔ or <-- Answer
the book is interesting.”
The notation q → p represents the statement “The book is interesting
✔ if <-- Answer
the book has pictures.”
Step-by-step explanation:
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