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DIA [1.3K]
3 years ago
6

For the function ƒ(x) = x2 – 4, find the value of ƒ(x) when x = 6.

Mathematics
2 answers:
Rus_ich [418]3 years ago
6 0

Answer:8

Step-by-step explanation:They said f(x)=x2–4 and they said find the value of f(x) when x=6

When x=6 you equate the value of x into the question

F(6)=6*2–4=8

Therefore the value of f(x) is 8

pashok25 [27]3 years ago
5 0

Answer:

f(x)= 2x -4

when x=6

f(x) = 2(6)-4

=12-4

=8

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Anita purchased a couch that was priced at $700. She will also have to pay 6% sales tax. How much will she pay in total for the
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Answer:

$742

Step-by-step explanation:

To solve this, you need to figure out what 6% of 700 dollars is and then add that to 700. The easiest way to find the percentage of a number is to set it up in the equation:

6/100 = x/700  where 6 is the percentage of 700 (out of 100 because you can only get up to 100 percent in this case) and x is 6 percent of 700. when you cross multiply, you get 100x = 4200. Then you divide both sides by 100 to get x by itself. This will give you x = 42 Add this to 700 for 742 as the total amount that will be paid. Sorry if this first half was a little confusing

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3 years ago
Carlos finds the absolute value of -5.3, and then finds the opposite of his answer. Jason finds the opposite of -5.3 and then fi
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The absolute value is how far away a number is from the number line, so it is always positive. If Carlos finds the opposite of the absolute value, that means he found the negative version. So Jason's final value will be greater.
4 0
3 years ago
Read 2 more answers
John wants to make a 100 ml of 6% alcohol solution mixing a quantity of a 3% alcohol solution with an 8% alcohol solution. What
mart [117]

Answer:

-50 ml of 3% alcohol solution and 150 ml of 8% alcohol solution

Step-by-step explanation:

For us to solve this type of mixture problem, we must represent the problem in equations. This will be possible by interpreting the question.

Let the original volume of the first alcohol solution be represented with x.

The quantity of the first alcohol solution needed for the mixture is 3% of x

                   ⇒ \frac{3}{100} * x

                       = 0.03x

Let the original volume of the second alcohol solution be represented with y.

The quantity of the second alcohol solution needed for the mixture is 5% of y

                   ⇒ \frac{5}{100} * y

                       = 0.05y

The final mixture of alcohol solution is 6% of 100 ml

                 ⇒ \frac{6}{100} * 100 ml

                       = 6 ml

Sum of values of two alcohol solutions = Value of the final mixture

                     0.03x + 0.05y = 6 ml               ..........(1)

Sum of original quantity of each alcohol solution = Original volume of the of mixture

                     x + y = 100 ml                          ..........(2)      

For easy interpretation, I will be setting up a table to capture all information given in the question.

Component                       Unit Value      Quantity(ml)       Value

3% of Alcohol solution        0.03                 x                     0.03x

8% of Alcohol solution        0.08                 y                     0.08y

Mixture of 100ml of 6%        0.06               100                       6    

                                                                x + y = 100       0.03x + 0.08y =6

Looking at the equations we derived, we have two unknowns in two equations which is a simultaneous equation.

                                0.03x + 0.05y = 6 ml               ..........(1)

                                x + y = 100 ml                           ..........(2)    

Using substitution method to solve the simultaneous equation.

Making x the subject of formula from equation (2), we have,

                                x  = 100 - y                                 ..........(3)

Substituting  x  = 100 - y from equation (3) into equation (1)

                               0.03(100 - y) + 0.05y = 6  

                               3 - 0.03y + 0.05y = 6  

Rearranging the equation,            

                               0.05y - 0.03y = 6 - 3

                               0.02y = 3

                               y = \frac{3}{0.02}

                               y = 150 ml

Substituting y = 150 ml into equation (3) to get x

                              x  = 100 - 150 ml

                              x = - 50 ml

The quantity of the first alcohol solution needed for the mixture for 3% is - 50 ml

The quantity of the second alcohol solution needed for the mixture for 5% is 150 ml

This solution means 50 ml of the first alcohol solution must be removed from the mixture with 150 ml of the second alcohol solution to get a final mixture of 100 ml of 6% alcohol solution.

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Which of the numbers below is less than zero? Select all that apply.
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