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Oduvanchick [21]
3 years ago
9

#savesheikhjarrah Let’s all pray for Palestine ♥️

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
3 0

Answer:

soi de perú         NO INGLISH IS SPANISH

Step-by-step explanation:

JAJAJAJ

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Xavier Martinez took out a $5,000 loan at 7.5% interest for reconstructing his patio. His monthly payment on the 12-month loan w
Norma-Jean [14]
Paying off the entire loan = 12 * 437.26 = <span> <span> <span> 5,247.12 </span> </span> </span>
He paid 6 * 437.26 = <span> <span> <span> 2,623.56 </span> </span> </span>
He then paid 2,556.03

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4 years ago
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Consider the function f given by f(x)=x*(e^(-x^2)) for all real numbers x.
NISA [10]

Answer:

\frac{\sqrt{\pi}}{4}

Step-by-step explanation:

You are going to integrate the following function:

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furthermore, you know that:

\int_0^{\infty}e^{-x^2}=\frac{\sqrt{\pi}}{2}

lets call to this integral, the integral Io.

for a general form of I you have In:

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furthermore you use the fact that:

I_n=-\frac{\partial I_{n-2}}{\partial a}

by using this last expression in an iterative way you obtain the following:

\int_0^{\infty}x^{2s}e^{-ax^2}dx=\frac{(2s-1)!!}{2^{s+1}a^s}\sqrt{\frac{\pi}{a}} (2)

with n=2s a even number

for s=1 you have n=2, that is, the function g(x). By using the equation (2) (with a = 1) you finally obtain:

\int_0^{\infty}x^2e^{-x^2}dx=\frac{(2(1)-1)!}{2^{1+1}(1^1)}\sqrt{\pi}=\frac{\sqrt{\pi}}{4}

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