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omeli [17]
3 years ago
9

Need help with question 3:) ASAp pls and thankyou

Mathematics
1 answer:
irga5000 [103]3 years ago
8 0
The answer to number 3 is (0,-2)
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(1/4) to the 3rd power
Ksivusya [100]
(1/4)=0.25
0.25*0.25*0.25=0.015625
6 0
3 years ago
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Can somebody help me on 23 and 24, it’s geometry
alexdok [17]

Answer:

  23.  x = 4; DE = 44

  24.  x = 25; DS = 28

Step-by-step explanation:

23. Point S is the midpoint of DE, so ...

  DS = SE

  3x +10 = 6x -2

  12 = 3x . . . . . . . . . add 2-3x

  4 = x . . . . . . . . . . . divide by 3

Then DS has length ...

  DS = 3x +10 = 12 +10 = 22

and DE is twice that length, so ...

  DE = 44

__

24. DS is half the length of DE, so is ...

  DS = DE/2 = 56/2

  DS = 28

Then x can be found from ...

  DS = x +3

  28 -3 = x = 25 . . . . . substitute value for DS

_____

<em>Comment on problem 24</em>

Sometimes it is easier to work parts of a problem out of sequence. Here, finding DS first makes finding x easier.

8 0
3 years ago
Read 2 more answers
How do you convert set notation to interval notation?
Semenov [28]

Answer:

Imagine we are to express  [ a , b ]  in set notation

A = [ a , b ] , then  A = { x  ∈  R  /  a ≤ x ≤ b }

In this notation we define the characteristics of all  x  belonging to this set  A ....x must be greater or equal to a and simultaneously smaller or equal to b...

Interval notation is other way to say the same but assuming that  means the extreme a is IN the interval and  means extreme  a  is not.

6 0
3 years ago
ПОЖАЛУЙСТА ПОМОГИТЕ РЕШИТЬ ДАЮ 23 ОЧКА!!!
posledela

(Простите, пожалуйста, мой английский. Русский не мой родной язык. Надеюсь, у вас есть способ перевести это решение. Если нет, возможно, прилагаемое изображение объяснит достаточно.)

Use the shell method. Each shell has a height of 3 - 3/4 <em>y</em> ², radius <em>y</em>, and thickness ∆<em>y</em>, thus contributing an area of 2<em>π</em> <em>y</em> (3 - 3/4 <em>y</em> ²). The total volume of the solid is going to be the sum of infinitely many such shells with 0 ≤ <em>y</em> ≤ 2, thus given by the integral

\displaystyle 2\pi \int_0^2 y \left(3-\frac34 y^2\right) \,\mathrm dy = 2\pi \left(\frac32 y^2 - \frac3{16} y^4\right)\bigg|_0^2 = 6\pi

Or use the disk method. (In the attachment, assume the height is very small.) Each disk has a radius of √(4/3 <em>x</em>), thus contributing an area of <em>π</em> (√(4/3 <em>x</em>))² = 4<em>π</em>/3 <em>x</em>. The total volume of the solid is the sum of infinitely many such disks with 0 ≤ <em>x</em> ≤ 3, or by the integral

\displaystyle \pi \int_0^3 \left(\sqrt{\frac43x}\right)^2 \,\mathrm dx = \frac{2\pi}3 x^2\bigg|_0^3 = 6\pi

Using either method, the volume is 6<em>π</em> ≈ 18,85. I do not know why your textbook gives a solution of 90,43. Perhaps I've misunderstood what it is you're supposed to calculate? On the other hand, textbooks are known to have typographical errors from time to time...

8 0
3 years ago
What is the value of 6P6?   A. 1   B. 36   C. 720   D. 46,656
il63 [147K]
6^6=6\cdot6\cdot6\cdot6\cdot6\cdot6=46,656\\\\Answer:D
3 0
3 years ago
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