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Nezavi [6.7K]
3 years ago
14

I really need help with this math problem quick!

Mathematics
1 answer:
Tatiana [17]3 years ago
4 0

Answer:

(8x^{6} y^{-3})^{2}  =  \frac{(8x^{6})^{2}}{(y^{3})^{2}} =\frac{64x^{12} }{y^{6}}

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Which expression is equivalent to 3(4m - 2) - 2(m + 5)
tangare [24]

Answer:

A. 10m - 16

Step-by-step explanation:

First, distribute 3 to all terms within the corresponding parenthesis, and -2 likewise:

3(4m - 2) =

3 * 4m = 12m

3 * -2 = -6

3(4m - 2) = 12m - 6

-2(m + 5) =

-2 * m = -2m

-2 * 5 = -10

-2(m + 5) = -2m -10

Combine like terms:

12m - 6  -2m - 10

12m - 2m - 6 - 10

(12m - 2m) + (-6 - 10)

10m - 16

A. 10m - 16 is your answer.

~

7 0
3 years ago
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How do you solve proportions
vladimir2022 [97]
You see, the thing is, you dont
3 0
4 years ago
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Y=-2x+5 was shifted down 7 units what equation is it now
baherus [9]

Answer:

y=-2x-2

Step-by-step explanation:

we have

y=-2x+5

This is the equation of a line in slope intercept form

where

m=-2 ---> the slope

b=5 ----> the y-intercept

we know that

If the given line was shifted down 7 units, then the new y-intercept is equal to

b=5-7=-2

The slope of the new line will be the same that the original line, because are parallel lines

so

The new equation is

y=-2x-2

3 0
4 years ago
Someone pls pls answer this ill mark u brainliest
Marysya12 [62]

Answer:

m\angle CBD=35^{\circ}

Step-by-step explanation:

Since there are 180^{\circ} on each side of a line and \angle ABC is marked as a right angle, m\angle CBE=180-90=90^{\circ}.

m\angle CBE=m\angle DBE+m\angle CBD, and m\angle DBE is given as 55^{\circ}.

Therefore, we can plug in our values and solve:

90=55+m\angle CBD,\\m\angle CBD=\fbox{35^{\circ}$}.

3 0
3 years ago
How to find the domain but the only value
Klio2033 [76]

Answer:

\frac{ - 3}{5}  \\

Step-by-step explanation:

to find the value not in the domain,

5x+3≠0

the. solve for its value

3 0
2 years ago
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