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3 years ago

Which is the correct one???

Mathematics

2 answers:

inysia [295]3 years ago

7 0

Answer:

x=12 Hope this helps!!!

Step-by-step explanation:

Remember a straight line equals 180 and when you have the box the angle is 90 degrees. Try solving the equation 5x-22+4x+4+90=180.

5x-22+4x+4+90=180 (combine like terms)

9x+72=180 (subtract 72 from both sides)

9x=108 (divide 9 on both sides)

x=12

Alik [6]3 years ago

6 0

Answer:

Step-by-step explanation:

5x-22+4x+4 = 90

9x-18=90

9x=108

x=12

4*12+4

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Can anyone help ? i really don’t understand this question <br> If NP bisects X =<br> m/RNM =

snow_tiger [21]

We can conclude that the value of x is (∠MNP + 66)/8 and angle m∠RNM = ∠RNQ - ∠MNP + 78.

<h3>What are angles?</h3>

An angle is a figure in Euclidean geometry formed by two rays, called the sides of the angle, that share a common endpoint, called the vertex of the angle.
Angles formed by two rays are located in the plane containing the rays.
Angles are also formed when two planes intersect.
These are known as dihedral angles.

So,

∠MNQ = ∠MNP + ∠PNQ
8x + 12 = ∠MNP + 78
8x + 12 - 78 = ∠MNP
8x - 66 = ∠MNP
8x = ∠MNP + 66
x = (∠MNP + 66)/8

Now, substitute 'x = (∠MNP + 66)/8' in 8x + 12:

∠MNQ = 8x + 12
∠MNQ = 8 ×(∠MNP + 66)/8 + 12
∠MNQ = ∠MNP + 66 + 12
∠MNQ = ∠MNP + 78

Hence, m∠RNM = ∠RNQ - ∠MNP + 78

Therefore, in the given question value of x is (∠MNP + 66)/8 and angle m∠RNM = ∠RNQ - ∠MNP + 78.

Know more about angles here:

brainly.com/question/25716982

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7 0

6 months ago

What is 8x-7(x+3)+5x

OLga [1]

Answer:

I'm not 100% sure love, but I think it would be 12x.

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Enter an equation in point-slope form for the perpendicular bisector of the segment with endpoints M(−3, 7) and N(9, −3). The po

scZoUnD [109]

Answer:

5y - 6x = 53

Step-by-step explanation:

Given the segment with endpoints M(−3, 7) and N(9, −3), let us find the slope first

m = y2-y1/x2-x1

m = -3-7/9-(-3)

m = -10/12

m = -5/6

Since the unknown line forms a perpendicular bisector, the slope of the unknown line will be:

m = -1/(-5/6)

m = 6/5

To get the intercept of the line, we will substitute m = 6/5 and any point on the line say (-3, 7) into the equation y = mx+c

7 = 6/5 (-3)+c

7 = -18/5 + c

c = 7 + 18/5

c = (35+18)/5

c = 53/5

Substitute m = 6/5 and c = 53/5

y = 6/5 x + 53/5

multiply through by 5

5y = 6x + 53

5y - 6x = 53

hence the point-slope equation of the perpendicular bisector is 5y - 6x = 53

6 0

2 years ago

Show that d^2y/dx^2=-2x/y^5, if x^3 + y^3=1

aalyn [17]

Answer:

y³ + x³ = 1

First, differentiate the first time, term by term:

${3y^{2}.\frac{dy}{dx} + 3x^{2}} = 0 \\\\{3y^{2}.\frac{dy}{dx} = -3x^{2}} \\\\\frac{dy}{dx} = \frac{-3x^{2}}{3y^{2}} \\\\\frac{dy}{dx} = \frac{-x^{2}}{y^{2}}$

↑ we'll substitute this later (4th step onwards)

Differentiate the second time:

$3y^{2}.\frac{dy}{dx} + 3x^{2} = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} + 6x = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{-x^{2} }{y^{2} })^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{x^{4} }{y^{4} }) = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + \frac{6x^{4} }{y^{3} } = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} = - 6x - \frac{6x^{4} }{y^{3} } \\\\$

$3y^{2}.\frac{d^{2} y}{dx^{2}} = - \frac{- 6xy^{3} - 6x^{4} }{y^{3}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{- 6xy^{3} - 6x^{4} }{3y^{2}. y^{3}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{- 2xy^{3} - 2x^{4} }{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x (y^{3} + x^{3})}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x (1)}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x}{y^{5}}$

3 0

2 years ago

What shape is the base of a hockey puck?<br> rectangle<br> circle<br> semi-circle<br> ellipse

ratelena [41]

Answer:circle

Step-by-step explanation:

5 0

2 years ago