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3 years ago

12

The school wants to buy a new speaker system for the football stadium with the money they raised from the bake sale.They compare

d speaker system prices from two different distribution
From school ‘R’Us a system t, costs $230 less than three times the price of the same speaker system ,d, at the The Warehouse the difference in price between the speaker system at school ‘R’Us and the Warehouse is $224
A. t-3d=-230
-t+d=224
B. 3t-d=-230
-t+d=224
C.t-3d=-230
t-d=224
D.3t-d=-230
t-d=224

1 answer:

ddd [48]3 years ago

6 0

C. would be the correct answer assuming that the end price of d is less than that of t.

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On an alien planet with no atmosphere, acceleration due to gravity is given by g = 12m/s^2. A cannonball is launched from the or

almond37 [142]

Answer:

a) $\vec r (t) = \left[(90\cdot \cos \theta)\cdot t \right]\cdot i + \left[(90\cdot \sin \theta)\cdot t -6\cdot t^{2} \right]\cdot j$ , b) $\theta = \frac{\pi}{4}$ , c) $y_{max} = 84.375\,m$ , $t = 3.75\,s$ .

Step-by-step explanation:

a) The function in terms of time and the inital angle measured from the horizontal is:

$\vec r (t) = [(v_{o}\cdot \cos \theta)\cdot t]\cdot i + \left[(v_{o}\cdot \sin \theta)\cdot t -\frac{1}{2}\cdot g \cdot t^{2} \right]\cdot j$

The particular expression for the cannonball is:

$\vec r (t) = \left[(90\cdot \cos \theta)\cdot t \right]\cdot i + \left[(90\cdot \sin \theta)\cdot t -6\cdot t^{2} \right]\cdot j$

b) The components of the position of the cannonball before hitting the ground is:

$x = (90\cdot \cos \theta)\cdot t$

$0 = 90\cdot \sin \theta - 6\cdot t$

After a quick substitution and some algebraic and trigonometric handling, the following expression is found:

$0 = 90\cdot \sin \theta - 6\cdot \left(\frac{x}{90\cdot \cos \theta} \right)$

$0 = 8100\cdot \sin \theta \cdot \cos \theta - 6\cdot x$

$0 = 4050\cdot \sin 2\theta - 6\cdot x$

$6\cdot x = 4050\cdot \sin 2\theta$

$x = 675\cdot \sin 2\theta$

The angle for a maximum horizontal distance is determined by deriving the function, equalizing the resulting formula to zero and finding the angle:

$\frac{dx}{d\theta} = 1350\cdot \cos 2\theta$

$1350\cdot \cos 2\theta = 0$

$\cos 2\theta = 0$

$2\theta = \frac{\pi}{2}$

$\theta = \frac{\pi}{4}$

Now, it is required to demonstrate that critical point leads to a maximum. The second derivative is:

$\frac{d^{2}x}{d\theta^{2}} = -2700\cdot \sin 2\theta$

$\frac{d^{2}x}{d\theta^{2}} = -2700$

Which demonstrates the existence of the maximum associated with the critical point found before.

c) The equation for the vertical component of position is:

$y = 45\cdot t - 6\cdot t^{2}$

The maximum height can be found by deriving the previous expression, which is equalized to zero and critical values are found afterwards:

$\frac{dy}{dt} = 45 - 12\cdot t$

$45-12\cdot t = 0$

$t = \frac{45}{12}$

$t = 3.75\,s$

Now, the second derivative is used to check if such solution leads to a maximum:

$\frac{d^{2}y}{dt^{2}} = -12$

Which demonstrates the assumption.

The maximum height reached by the cannonball is:

$y_{max} = 45\cdot (3.75\,s)-6\cdot (3.75\,s)^{2}$

$y_{max} = 84.375\,m$

7 0

3 years ago

HELP FASTTTT Which graph shows the solution to the system of linear inequalities ?

Mice21 [21]

Well, we do not see the lines clearly (if they are dotted (inequality) or solid (inequality or equal) ), but we'll come back to this.

y<x+1 can be simplified to be y<x if we ignore the constants, so the valid part is BELOW the line, since (y<)

x-4y <=4
again, ignore the constants and simplify to
x-y<0 or
y>x so the valid part is ABOVE the line (since y>)

There are two graphs that satisfy BOTH conditions, pink (slope=1) at the bottom, and blue (slope = 1/4) on top, i.e. first and third graph.

For the absolute inequality (y<x+1), the red line must be dotted.
For the <= condition, the blue line must be solid.

As we cannot see the lines clearly, you will make the choice between the first and third graphs according to the previous paragraph.

4 0

3 years ago

Read 2 more answers

foston is between liberty and west qual and is 4 inches from liberty in the map. how far is foston from west quall

Kobotan [32]

In order to calculate that distance, we need to know the
" scale " of the map ... how many miles is represented by
1 inch on the map, or the ratio.

Different maps are drawn with different scales.

4 0

3 years ago

Pls help I tried basic answers like 50+50+80 =180 but it’s wrong so pls help

PilotLPTM [1.2K]

Answer:

x = 65 degrees

Step-by-step explanation:

x° + x° + 50° = 180°

2x + 50° = 180°

2x = 180° - 50°

2x = 130°

x = 130°/2

x = 65°

5 0

3 years ago

Your team wins 18 medals at a competition. The metals are gold, silver, and bronze in a ratio of 2:4:3. How many of each metal d

Anarel [89]

Answer

Find out the how many of each metal did your team win.

To prove

As given

Your team wins 18 medals at a competition.

The metals are gold, silver, and bronze in a ratio of 2:4:3.

Let us assume that x be the scalar multiple of the gold, silver and bronze medal.

Thus

Number of gold medal = 2x

Number of silver medal = 4x

Number of bronze medal = 3x

Than the equation becomes

2x + 4x + 3x = 18

9x = 18

$x = \frac{18}{9}$

x = 2

Number of gold medal = 2 × 2

= 4

Number of silver medal = 4 × 2

= 8

Number of bronze medal = 3 × 2

= 6

Therefore the number of gold medal are 4, silver medal are 8, bronze medal are 6.

3 0

3 years ago