Find value of m either add or subtract for m
I think it's 90% sorry if I'm wrong
Answer:
1 3/4
Step-by-step explanation:
First write the equation in mixed fraction form as;
1 3/4 + 1 1/3 = 1 _/12 + 1 4/12 ⇒ 7/4 + 4/3 = _ + 16/12
7/4 + 4/3 = _ + 16/12
37/12 = _ + 16/12
37/12 - 16/12 = _
= 21/ 12
= 1 9/12
= 1 3/4
<span>64-40ab
=8(8-5ab)
....................................</span>
Answer:
![h(x)=12x-9](https://tex.z-dn.net/?f=h%28x%29%3D12x-9)
Step-by-step explanation:
We are given the two functions:
![f(x)=4x-2\text{ and } g(x)=-8x+7](https://tex.z-dn.net/?f=f%28x%29%3D4x-2%5Ctext%7B%20and%20%7D%20g%28x%29%3D-8x%2B7)
And we want to find:
![h(x)=f(x)-g(x)](https://tex.z-dn.net/?f=h%28x%29%3Df%28x%29-g%28x%29)
So, by substitution:
![h(x)=(4x-2)-(-8x+7)](https://tex.z-dn.net/?f=h%28x%29%3D%284x-2%29-%28-8x%2B7%29)
Simplify. Distribute:
![h(x)=(4x-2)+(8x-7)](https://tex.z-dn.net/?f=h%28x%29%3D%284x-2%29%2B%288x-7%29)
Rearrange:
![h(x)=(4x+8x)+(-2-7)](https://tex.z-dn.net/?f=h%28x%29%3D%284x%2B8x%29%2B%28-2-7%29)
Combine like terms. Hence:
![h(x)=12x-9](https://tex.z-dn.net/?f=h%28x%29%3D12x-9)