Answer:
P = 10/171
P = 0.058
The probability that both fish selected are Catfish is 0.0058
Step-by-step explanation:
Given:
The tank contains;
Algae eaters = 8
Catfish = 5
Tilapia fish = 6
Total number of fish = 8+5+6= 19
To determine the probability that both fish selected are Catfish P;
P = 5/19 × 4/18
( The number of the total number of fishes, and Catfish reduce by one after each selection because it is selected without replacement)
P = 10/171
P = 0.058
I don’t know hekndssndidnbeyehebnrdidbdbkdndnfhndmdkdnnddo
Answer:
a) Yes, the two variables correlated
b) Yes, variation of sugar changes the number of orders for item containing sugar
Step-by-step explanation:
a) Yes the two variables are moderately co-related as the value of co-relation lies between 0.5 and 0.7
b) Yes the variation in amount of sugar leads to variation in the number of orders with sugar.
the step by step instructions r in the pics
Part 1
We want to find the tan of 88 degrees, 22' 45''.
88° 22' 45''
= 88 + 22/60 + 45/3600 degrees
= 88.3792°
From the calculator, obtain
tan(88.3792°) = 35.3409
Answer: 35.3409
Part 2
We want to find cot(36°).
By definition, cot(x) = 1/tan(x).
From the calculator, obtain
tan(36°) = 0.7265
Therefore
cot(36°) = 1/0.7265 = 1.3764
Answer: 1.3764
