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NeX [460]
4 years ago
9

What is the area of the composite figure whose vertices have the following coordinates? (−1, 5) , (3, 5) , (7, 3) , (3, 0) , (−1

, 1) Enter your answer in the box. units²

Mathematics
1 answer:
trasher [3.6K]4 years ago
5 0
We can see the figure as two triangles and a square.
 We have then:
 Area of the square:
 
A1 = (4) * (4)
 A1 = 16
 Area of the small triangle:
 
A2 = (1/2) * (4) * (1)
 A2 = 2
 Area of the big triangle:
 
A3 = (1/2) * (5) * (4)
 A3 = 10
 The area of the figure is:
 
At = A1 + A2 + A3
 At = 16 + 2 + 10
 At = 28units²
 Answer:
 
The area of the figure is:
 
At = 28units²
 
Note: see attached image

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Simplify 3/4-4x+1/2x-1/2+1/2x
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7 0
4 years ago
Auditoriums are often designed so that are fewer seats per row for rows closer to the stage. Suppose you are sitting in row 18 i
zhannawk [14.2K]

Answer:

(a) 22 (b) 109

Step-by-step explanation:

GIVEN: Auditoriums are often designed so that are fewer seats per row for rows closer to the stage. Suppose you are sitting in row 18 in an auditorium and notice that there are 73 seats in your row. It appears the row in front of you has 70 seats and the row behind you has 76 seats. Suppose this pattern continues throughout the auditorium.

TO FIND: a) How many seats are in the first row b) How many seats are in the 30th row?

SOLUTION:

total seats in row_{19}=76

total seats in row_{18} =73

total seats in row_{17}=70

as it clearly form an A.P. with d=76-73=3

(a)

let total seat in first row be a

as total seats in row_{18}=73

row_{18}=a+(n-1)d

73=a+17\times3

a=22

total seats in first row are 22

(b)

total seats in 30th be x

x=row_{1}+(30-1)3

x=22+29\times3

x=109

total seats in 30th row  are 109

4 0
3 years ago
What is the area of sector?
Shtirlitz [24]

Answer:

a

Step-by-step explanation:

since 90 degrees is 1/4 of a circle, the area of the sector is 5²pi/4 = 25/4pi = 19.63

5 0
3 years ago
WILL GIVE BRAINLIEST!
Nataly [62]

Answer:

The equation the circle is given by

{\bf 4x}^{\bf 2}+{\bf 4y}^{\bf 2}-{\bf 8x+0y-60}={\bf 0}

Step-by-step explanation:

The general form of the circle is

x^2+y^2+Dx+Ey+F=0\hfill (1)

Given points are (5,0) , (0,4) and (2,4)

Let the points (5,0) , (0,4) and (2,4) be (x_1,y_1) , (x_2,y_2) and (x_3,y_3) respectively

The equation of the circle passes through given points (5,0) , (0,4) and (2,4)

Substituting the point (5,0) in (1)

(-5)^2+(0)^2+D(5)+E(0)+F=0

25-5D+F=0

5D-F=25\hfill (2)

Substituting the point (0,4) in

(0)^2+(4)^2+D(0)+E(4)+F=0

16+4E+F=0

4E+F=-16\hfill (3)

Substituting the point (2,4) in

(2)^2+(4)^2+D(2)+E(4)+F=0

4+16+2D+4E+F=0

2D+4E+F=-20\hfill (4)

By solving the equations (2) ,(3) and(4) we get the values of D,E and F as below

D=-2  , E=0  and F=-15

substituting the values of D,E and F in (1) we get

x^2+y^2-2x+(0)y-15=0

Now multiplying the above equation into 4 we get

4x^2+4y^2-8x+(0)y-60=0

6 0
3 years ago
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