What is the area of the composite figure whose vertices have the following coordinates? (−1, 5) , (3, 5) , (7, 3) , (3, 0) , (−1
, 1) Enter your answer in the box. units²
1 answer:
We can see the figure as two triangles and a square.
We have then:
Area of the square:
A1 = (4) * (4)
A1 = 16
Area of the small triangle:
A2 = (1/2) * (4) * (1)
A2 = 2
Area of the big triangle:
A3 = (1/2) * (5) * (4)
A3 = 10
The area of the figure is:
At = A1 + A2 + A3
At = 16 + 2 + 10
At = 28units²
Answer:
The area of the figure is:
At = 28units²
Note: see attached image
We have then:
Area of the square:
A1 = (4) * (4)
A1 = 16
Area of the small triangle:
A2 = (1/2) * (4) * (1)
A2 = 2
Area of the big triangle:
A3 = (1/2) * (5) * (4)
A3 = 10
The area of the figure is:
At = A1 + A2 + A3
At = 16 + 2 + 10
At = 28units²
Answer:
The area of the figure is:
At = 28units²
Note: see attached image
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Answer:
The answer is
<h2>3x + 2y = 28</h2>Step-by-step explanation:
To find an equation of the line using a point and the slope we use the formula
y - y1 = m(x - x1)
where
m is the slope
(x1 , y1) is the point
From the question
slope = -3/2
Point = (4,8)
So the equation of the line is
Multiply through by 2
2y - 16 = -3( x - 4)
2y - 16 = - 3x + 12
3x + 2y = 16 + 12
We have the final answer as
<h3>3x + 2y = 28</h3>Hope this helps you
Answer:
Taking data:
28 78 74 89 72
50 55 66 26 84
59 64 88 23 27
70 63 42 37 29
The answer is
Step-by-step explanation:
As the data is not given in the question i'm guessing the data from the question i solved before
28 78 74 89 72
50 55 66 26 84
59 64 88 23 27
70 63 42 37 29
as taking the above data,
As we know for finding the width of class:
≈
Note : By using the above given formula you can calculate the width of any data just by taking the maximum and minimum values of data and the number of classes the data is divided into.