Given: f(x) = 9 cos (2x)
The differential equation is df = - 18 sin(2x) dx
When x contrasts from π/6 to π/6 + 01, then dx = 0.1.
The variation in f is δf = - 18 sin(π/3) *(0.1) = -1.5588 ≈ -1.559
The computation in the change in f directly:
f(π/6) = 9 cos(π/3) = 4.5
f(π/6 + 0.1) = 9 cos(π/3 + 0.2) = 2.6818
δf = 2.6818- 4.5 = -1.6382 ≈ -1.638
Direct computation of δf is near to the real value but in error.
The two outcomes will be closer as dx gets smaller.
Answer would be:
δf = -1.559 (correct answer)
δf = -1.638 (approximate answer)
98 is the answer.
The 8 is in the tens place and the number in the ones place is greater than the number in the tens place.
Answer:
1, x/3, x^2/9, x^3/27, x^4/81
x^4 +3x^3+9x^2+27x+81
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81
Step-by-step explanation:
(x/3) ^i
i=0 (x/3)^0 = 1
i=1 (x/3)^1 = x/3
i=2 (x/3)^2 = x^2/3^2 = x^2/9
i=3 (x/3)^3 = x^3/3^3 =x^3/27
i=4 (x/3)^4 = x^4/3^4 =x^4/81
The sum is
1+(x/3) + x^2/9 + x^3/27 + x^4/81
We need a common denominator of 81
1*81/81 + x/3 *27/27 + x^2/9 *9/9 + x^3/27 *3/3 + x^4/81
81+27x + 9x^2 + 3x^3 +x^4
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81
Rewriting from largest power to smallest power
x^4 +3x^3+9x^2+27x+81
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81
Answer:
4/3x -5
Step-by-step explanation:
