Answer:
The explicit form is 
Step-by-step explanation:
The explicit form of a geometric sequence is given by:

where an is the nth term, a is the first term of the sequence and r is the common ratio.
In this case:
a=162
The value of the common ratio is obtained by dividing one term by the previous term.
For the first and second terms:
108/162=2/3
For the second and third terms (In order to prove that 2/3 is the common ratio)
72/108=2/3
Therefore:
r=2/3
Replacing a and r in the formula:

Answer:
4.6
Step-by-step explanation:
Hello!
To find the average we add all the numbers together and divide by how many numbers we added
6.8 + 5.6 + 3.4 + 2.5 + 4.7 = 23
We added 5 numbers so divide the total by 5
23/5 = 4.6
The answer is 4.6
Hope this helps!
Answer:
Subtract from both sides of the equation the term you don't want
Step-by-step explanation:
In solving equations, you generally want to "undo" operations that are done to the variable. Addition is "undone" by adding the opposite (that is, subtracting the amount that was added). Multiplication is "undone" by division.
If you have variables on both sides of the equation, pick one of the variable terms and subtract it from both sides of the equation.
<u>Example</u>
2x = x +1
If we choose to subtract x, then we will have a variable term on the left and a constant term on the right:
2x -x = x -x +1 . . . . . . . x is subtracted from both sides
x = 1 . . . . . . simplify
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Note that we purposely set up this example so that removing the variable term from the right side caused the variable term and constant term to be on opposite sides of the equal sign. It may not always be that way. As long as you remember that an unwanted term can be removed by subtracting it (from both sides of the equation), you can deal with constant terms and variable terms no matter where they appear.
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<em>Additional Comment</em>
It usually works well to choose the variable term with the smallest (or most negative) coefficient. That way, when you subtract it, you will be left with a variable term that has a positive coefficient.
Step-by-step explanation:
Answer : 5r−4x+5
hope I helped c:
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