The sum of the function will be (r – s)(x) = –2x² + x – 3, The difference of the function will be (r – s)(x) = –2x² + x – 3, and The product of the function will be (r × s)(x) = 2x³ – 6x².
The complete question is attached below.
<h3>What is Algebra?</h3>
The analysis of mathematical representations is algebra, and the handling of those symbols is logic.
The functions are given below.
r(x) = x – 3
s(x) = 2x²
The sum of the function will be
(r + s)(x) = x – 3 + 2x²
(r + s)(x) = 2x² + x – 3
The difference of the function will be
(r – s)(x) = (x – 3) – 2x²
(r – s)(x) = –2x² + x – 3
The product of the function will be
(r × s)(x) = (x – 3) (2x²)
(r × s)(x) = 2x³ – 6x²
More about the Algebra link is given below.
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Answer:
6 and 8
Step-by-step explanation:
All you have to do is find the difference between the numbers in each factor pair and make sure the factors combine to give 48.
2 and 4 . . . . . have a difference of 2, but 2·4 ≠ 48
4 and 6 . . . . . have a difference of 2, but 4·6 ≠ 48
6 and 8 . . . . . have a difference of 2, and 6·8 = 48
24 and 2 . . . . do not have a difference of 2
Answer:
See the proof below
Step-by-step explanation:
For this case we need to proof the following identity:
We need to begin with the definition of tangent:
So we can replace into our formula and we got:
(1)
We have the following identities useful for this case:
If we apply the identities into our equation (1) we got:
(2)
Now we can divide the numerator and denominato from expression (2) by 
and we got this:
And simplifying we got:
And this identity is satisfied for all:
Area of triangle = 1/2 bh
60 = 1/2 (15) h
8 = h
Quadrilateral area = h x (b1 + b2)/2 = 8 x (15+9)/2 = 96 sq units
96 -60 = triangle BAD area = 36 sq units
2x+2 < x+3
2x-x < 3-2
x <1
