1: I can’t see one it’s cut out sorry :(
2:go down four horrizontal for each line making a rhombus
3: 3a:true 3b:true 3c:false 3D: false
4.PART A: Draw a square in the middle.
4. PART B: Say there are four right angles
5: Line, point, ray, line segment
6. There are 2 acute and 1 right
7. A B C
8: 1/4 1/6 1/8
9: 9a 9c and 9d
10: square and polygons first, then triangles because they have 4 sides while a triangle has 3
10 PART B: rectangles second, then the pentagons are third, the parallelogram is first, then the triangles because a rectangle has all right angles
11: she drew a square!
12: polygons without right angles
13: I can’t draw on your paper just draw three lines in the trapezoid
13: a c and d
I’m not sure but I’m commenting Bc I really need an answer I’m so sorry
The distance Jada is from starting point will be found using the cosine formula:
c²=a²+b²-2abCos C
a=200, b=90, C=70°
thus plugging in our values we get:
c²=200²+90²-2×200×90×cos70
c²=40000+8100-36000(0.3420)
c²=35788
hence
c=189.1772 m'
therefore the distance Jada is from the starting point is 189.1772 m
