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melomori [17]
3 years ago
13

Which statement is true? A. In any right triangle, the sine of one acute angle is equal to the cosine of the other acute angle.

B. In any right triangle, the sine of one acute angle is equal to the sine of its complementary angle. C. In any right triangle, the cosine of one acute angle is equal to the cosine of its complementary angle. D. In any right triangle, the sum of the sine of one acute angle and the cosine of the other acute angle is 1.
Mathematics
2 answers:
mr Goodwill [35]3 years ago
8 0

That would be choice 2. One acute angle is the complement of the other

eg in a 90-60-30 triangle sine 30 = cos 60

Mademuasel [1]3 years ago
6 0

The correct answer is B. In any right triangle, the sine of one acute angle is equal to the sine of its complementary angle.

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What is the original price:$65.00; Markdown: 12%
alexandr1967 [171]
The answer to this question is $57.02
6 0
3 years ago
"Find the sum of the first 50 term in this sequence 4, 7, 10, 13, ...". How do i do this without writing them all out, and how d
melisa1 [442]
First term ,a=4 , common difference =4-7=-3, n =50
sum of first 50terms= (50/2)[2×4+(50-1)(-3)]
=25×[8+49]×-3
=25×57×-3
=25× -171
= -42925
derivation of the formula for the sum of n terms
Progression, S
S=a1+a2+a3+a4+...+an

S=a1+(a1+d)+(a1+2d)+(a1+3d)+...+[a1+(n−1)d]   →   Equation (1)

S=an+an−1+an−2+an−3+...+a1

S=an+(an−d)+(an−2d)+(an−3d)+...+[an−(n−1)d]   →   Equation (2)

Add Equations (1) and (2)
2S=(a1+an)+(a1+an)+(a1+an)+(a1+an)+...+(a1+an)

2S=n(a1+an)
S=n/2(a1+an)

Substitute an = a1 + (n - 1)d to the above equation, we have
S=n/2{a1+[a1+(n−1)d]}
S=n/2[2a1+(n−1)d]
5 0
3 years ago
HELP PLS WILL GIVE A LOT OF POINT
sveta [45]

Answer:

large = 18 3/4 = 18.75

small = 13/2 = 6 1/2 = 6.5

Step-by-step explanation:

Let l = the weight of large boxes

s = weight of small boxes

2 large and 3 small weights 57

2l+3s = 57

6 large and 5 small wights 145

6l+5s = 145

Multiply the first equation by 3

3(2l+3s) = 57*3

6l +9s =171

Subtract the second equation

6l +9s =171

-6l -5s = -145

-----------------------

     4s =26

Divide each side by 4

4s/4 = 26/4

s = 26/4 = 13/2

Substitute this into the first equation

2l +3s = 57

2l + 3(13/2) =57

Multiply by 2 to get rid of the fractions

2(2l + 3(13/2)) =57*2

4l + 39 = 114

Subtract 39 from each side

4l +39-39 = 114-39

4l =75

Divide by 4

4l/4 = 75/4

l = 75/4 = 18 3/4

7 0
3 years ago
Read 2 more answers
Find the line y=a+bx which best approximates the data points
Vika [28.1K]

Answer:

y = 11.84x - 32.71

Step-by-step explanation:

Here, the given data points,

(−3,−70),(−1,−42),(1,−21),(2,−9),(4,14),

Let x represents the input value and y represents the output value,

So, the table that represents the given situation is,

x         -3            -1             1             2             4

y       -70          -42         -21         -9             14

By the above table,

\sum x=3

\sum y=-128

\sum xy = 269

\sum x^2=31

\sum y^2 = 7382

Let the equation of the line is,

y = bx + a

Where,

a=\frac{\sum y \sum x^2 - \sum x\sum xy}{n(\sum x^2)-(sum x)^2}

b=\frac{n\sum xy - \sum x \sumy}{n(\sum x^2)-(\sum x)^2}

n = number of data points = 5,

By substituting the values we get,

a = - 32.70547945 ≈ - 32.71,

b = 11.84246575 ≈ 11.84,

Hence, the equation of line would be,

y = 11.84x - 32.71

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3 years ago
ΔDOG has coordinates D (3, 2), O (2, −4) and G (−1, −1). A translation maps point D to D' (2, 4). Find the coordinates of O' and
geniusboy [140]

Answer:

see explanation

Step-by-step explanation:

Given D(3, 2 ) → D'(2, 4 )

The x- coordinate of D' is 1 less than D and the y- coordinate of D' is 2 more than D, thus the translation rule is

(x, y ) → (x - 1, y + 2 )

Apply this rule to points O and G

O( 2, - 4 ) → O'(2 - 1, - 4 + 2 ) → O'(1, - 2 )

G(- 1, - 1 ) → G'(- 1 - 1, - 1 + 2 ) → G'(- 2, 1 )

6 0
3 years ago
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