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lora16 [44]
2 years ago
8

Adding integers (+6)+(+2)

Mathematics
1 answer:
noname [10]2 years ago
7 0

Answer:

6 + 2=8 \\so... +2 + +6 = +8\\

Step-by-step explanation:

So the thing about adding of integers is that is both nos. are positive then you can simply add it and same with negative too.But with negative and positive we should subtract but that is for later.Luckily we have 2 positive integers so we do it like this:

+6 is the same as 6 and +2 is the same as 2 so we...

  rule:add the numbers and add the sign.

6 + 2=8\\so... +2 + +6 = +8

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Tony’s Electronics is marking down the price of a TV 23% from the original price of $175. Which expression can be used to find t
Arlecino [84]

Answer:

The sale price is \$134.75

The expression is \$175(0.77)

Step-by-step explanation:

we know that

The sale price is equal to subtract the discount price from the original price

The discount price is equal to multiply the original price by the percent discount in decimal form

Let

x ----> the sale price

y ---> discount price

23\%=23/100=0.23 ----> percent discount in decimal form

y=\$175(0.23)=\$40.25

x=\$175-y

substitute

x=\$175-\$40.25=\$134.75

therefore

the expression is

175-0.23(175)\\175(1-0.23)\\175(0.77)

3 0
3 years ago
Read 2 more answers
I need help with this question
Dafna1 [17]

since you have 11 cards and need to know how many red and black

 r+b needs to equal 11

 since r+b=11 isn't shown in any answer then none of them are correct, so none of the above

3 0
3 years ago
Drag a statement or reason to each box to complete this proof.
IRISSAK [1]

Answer:

3 Reasons) Transitive Property of congruence

4 Statements) JN =~ NK

5 Statements) MN =~ NK

6 Reasons) Definition of an isosceles triangle

Hope that helps!


7 0
3 years ago
Which of the following values is the 25th percentile?lower quartile, median, upper quartile
lawyer [7]
The lower quartile is the 25th percentile.
7 0
2 years ago
Read 2 more answers
Find how many solutions there are to the given equation that satisfy the given condition.
den301095 [7]

Answer:

17550 solutions

Step-by-step explanation:

Given that:

y1 +y2+y3+y4=27

where;

(yi  ≥ 0 and yi \epsilon {\displaystyle \mathbb {Z} }  )

The no. of a nonnegative integer determines the number of ways to choose 27 objects from (4) distinct objects with repetition regardless of the order.

i.e

\bigg(^{27}_{4} \bigg)

∴

The number of nonnegative integer solution is \bigg(^{27}_{4} \bigg)

= \dfrac{27!}{4!(27-4)!}

= \dfrac{27!}{4!(23)!}

= \dfrac{27\times 26\times 25\times 24 \times  23 !}{4\times 3\times 2\times 1(23)!}

= \dfrac{27\times 26\times 25\times 24 }{4\times 3\times 2\times 1}

= \dfrac{421200}{24}

= 17550 solutions

7 0
2 years ago
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