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dezoksy [38]
3 years ago
7

Find the vertical asymptote(s) of f of x equals quantity 4 x squared plus 3x plus 6 end quantity over quantity x squared minus 3

6
Mathematics
1 answer:
siniylev [52]3 years ago
4 0

The vertical asympototes of f(x) are  at x = -6 and x = 6

Step-by-step explanation:

To find the vertical asymptote(s) of a rational function,

  • Equate the denominator by 0
  • Solve it for x
  • If x = a, then the vertical asymptote is at x = a

∵ f(x)=\frac{4x^{2}+3x+6}{x^{2}-36}

- Equate the denominator x² - 36 by 0

∵ x² - 36 = 0

- Add 36 to both sides

∴ x² = 36

- Take √ for both sides

∴ x = ± 6

∴ There are vertical asymptotes at x = -6 and x = 6

The vertical asympototes of f(x) are  at x = -6 and x = 6

Learn more:

You can learn more about the asymptotes in brainly.com/question/6459599

#LearnwithBrainly

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Please help me with this one.​
Degger [83]

Answer:

  2x^2 -x +1 = 0

Step-by-step explanation:

For roots α and β, the original equation can be factored as ...

  f(x) = 2(x -α)(x -β)

If we add 1 to each of those roots, the factors become ...

  g(x) = 2(x -(α+1))(x -(β+1))

This can be rearranged to be ...

  g(x) = 2((x -1) -α)((x -1) -β)

That is, we can get the desired equation by replacing x with x-1, effectively shifting the function right one unit.

  2(x -1)² +3(x -1) +2 = 0

  2x^2 -x +1 = 0

5 0
3 years ago
Can anyone help me?
ArbitrLikvidat [17]

Answer:

The factored form of 4<em>m</em>³ – 28<em>m</em>² – 120<em>m</em> is 4<em>m</em>(<em>m</em> – 10)(<em>m</em> + 3). The zeroes of the function would be <em>m</em> = 0, <em>m</em> = –3, and <em>m</em> = 10.

Step-by-step explanation:

I'll give this a shot.

4<em>m</em>³ – 28<em>m</em>² – 120<em>m</em> = 0 — The original expression

4<em>m</em>³ – 28<em>m</em>² – 120<em>m</em> — Did that 0 have any purpose? I just deleted it.

4(<em>m</em>³ – 7<em>m</em>² – 30<em>m</em>) — There's a common factor in here, 4. Let's pull that aside.

4m(<em>m²</em> – 7<em>m</em> – 30) — Actually, there's <em>two</em> common factors. The second one is <em>m</em>! Let's pull <em>that</em> out too!

To factor an expression, you have to break apart the middle term, so to speak. That's only possible if you can find two numbers whose product equals that of the outside terms and whose sum equals the middle term. Here, I'm just dealing with numbers and putting that variable aside.

–30 = 10 × –3

–30 = –10 × 3

–30 = –2 × 15

–30 = 2 × –15 — To solve for any potential factors, let's find all the numbers integers that multiply to –30

Now let's see which one adds up to –7!

15 – 2 = 13 — it's not this one

2 – 15 = –13 — nor this one

10 – 3 = 7 — we're pretty close! Let's switch that negative

3 – 10 = –7 — here we go! Here's our numbers!

4<em>m</em>[(<em>m</em>² – 10<em>m</em>) + (3<em>m</em> – 30)] — now we break apart the middle term. This is <em>all</em> multiplied by 4<em>m</em>, so that still encases everything with brackets.

4<em>m</em>[<em>m</em>(<em>m</em> – 10) + 3(<em>m</em> – 10)] — Factoring the two expressions

4<em>m</em>(<em>m</em> + 3)(<em>m</em> – 10) — simplifying to find our answer! Ta-da!

8 0
3 years ago
Whats 90 divided by 2 times 5
Allisa [31]

Answer:

225

Step-by-step explanation:

90 divided by 2 is 45, 45 times 5 is  225

4 0
3 years ago
Read 2 more answers
Hey can someone help:)?​
Zolol [24]
I think it’s the first one
7 0
3 years ago
Talib is trying to find the inverse of the function to the right. His work appears beneath it. Is his work correct? Explain your
ololo11 [35]
No, they forgot to switch variable labels after solving for the independent variable...

y=-8x+4

y-4=-8x

(y-4)/-8=x 

Now that you have solved for the independent variable x, you switch the variable labels...

y=(x-4)/-8

f^-1(x)=(x-4)/-8     which should really be rewritten as:

f^-1(x)=(4-x)/8  :P
3 0
3 years ago
Read 2 more answers
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