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The first one is number 2 the second one is 185.(could you also say what is in the drop down menu for the third one. The last one is Part A is 376 and part B is 1,3,4.Hoped it helped a bit :)
Answer:

Find the midsegment of the triangle which is parallel to CA.

Tip
- A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle.
- This segment has two special properties. It is always parallel to the third side, and the length of the midsegment is half the length of the third side.
- If two segments are congruent, then they have the same length or measure.In other words, congruent sides of a triangle have the same length.

We have to find the segment which is parallel to CA.
From the given data,
The segment EG is the midsegment of the triangle
ABC.
So we have,
A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle. This segment has two special properties. It is always parallel to the third side.

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Answer:
I think it’s A, Good luck!
Step-by-step explanation:
Answer:
Step-by-step explanation:
height of pyramid = √(10²-(5/2)²) = √93.75
volume of pyramid = ⅓b²h = ⅓·5²√93.75 ≅ 80.69 in³
lateral area = 2×5×10 = 100 in²
base area = 5² = 25 in²
surface area = 100+25 = 125 in²