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NikAS [45]
2 years ago
10

You deposit $1500 into a savings account that pays 6% interest compounded yearly. How much money is in the account after 10 year

s assuming you made no additional deposits or withdrawals
Mathematics
2 answers:
OlgaM077 [116]2 years ago
6 0
Dudes diidlidododidododododkkcicofcoofgpofootfokclckxkxkxdiididodkdkxkc trjhnsemrejejejgckswkwjsssjszjduuuiffkhdzhjdyyshzxixuiffiidjxjxjcjxxjxjjzxkjdjxidjxjxifjxuxuxhxh UCB. Xhudidxjjcficiudjdjcjxdkcofofkcixdizuusjzjdkkxkxodjzjzjxjxkcofkckcicofcojxjxkcjxxkxmdkdkhxjxj j xjjxxjhxudxjxjidiszjhsxhhxxhuxxuhxjxujxxixjj h duudxjxhxuj. J ji cjuckvxhj ya thx jtsjcyssgzyxyxyv
Phantasy [73]2 years ago
5 0

Answer:

$2,686.27

Step-by-step explanation:

1500(1+.06)^10

It is .06 because you have to convert it into a decimal.

Which gives you the answer of $2,686.27

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Homework:Assignment 3 Question 20 Score: 0 of 1 point A vending machine dispenses coffee into ​-ounce cup. The amount of coffee
xxMikexx [17]

Answer:

19.92

Step-by-step explanation:

To overfill 5% of the time ;

The Zscore (value) to the left of (1 - 0.05) = 0.95 is 1.645

Using this Zscore value with the Zscore formula :

Zscore = (x - μ) / σ

σ = 0.05 ; x = 20 ounce

Substituting into the Zscore formula :

1.645 = (20 - μ) / 0.05

1.645*0.05 = 20 - μ

0.08225 = 20 - μ

μ = 20 - 0.08225

μ = 19.91775

μ = 19.92

8 0
3 years ago
Someone please help!!!!​
Ber [7]

Answer:

60

Step-by-step explanation:

3 0
3 years ago
What is the value of the 10th term in this arithmetic sequence? <br><br>2,5,8,11,...
yKpoI14uk [10]
It looks to be 29, if the rule is to add 3z
8 0
3 years ago
Dale deposits $4000 into an account that pays simple interest at a rate of 6% per year. How much interest will he be paid in the
BartSMP [9]

Answer:

$1200

Step-by-step explanation:

$4000 x .06 = $240 x 5 years = $1200

7 0
3 years ago
Situation:
Gala2k [10]

Answer:

5.5 days (nearest tenth)

Step-by-step explanation:

<u>Given formula:</u>

\sf N=N_0e^{-kt}

  • \sf N_0 = initial mass (at time t=0)
  • N = mass (at time t)
  • k = a positive constant
  • t = time (in days)

Given values:

  • \sf N_0 = 11 g
  • k = 0.125

Half-life:  The <u>time</u> required for a quantity to reduce to <u>half of its initial value</u>.

To find the time it takes (in days) for the substance to reduce to half of its initial value, substitute the given values into the formula and set N to half of the initial mass, then solve for t:

\begin{aligned}\sf N & = \sf N_0e^{-kt}\\\\\implies \sf \dfrac{11}{2} & = \sf 11e^{-0.125t}\\\\\sf \dfrac{1}{2} & = \sf e^{-0.125t}\\\\\sf \ln \left(\dfrac{1}{2}\right) & = \sf \ln e^{-0.125t\\\\\sf \ln \left(\dfrac{1}{2}\right) & = \sf -0.125t \ln e\\\\\sf \ln \left(\dfrac{1}{2}\right) & = \sf -0.125t(1)\\\sf t & = \sf \dfrac{\ln \left(\dfrac{1}{2}\right)}{-0.125}\\\\\sf t & = \sf 5.545177444...\\\\\sf t & = \sf 5.5\:\:days\:\:(nearest\:tenth)\end{aligned}

Therefore, the substance's half-life is 5.5 days (nearest tenth).

Learn more about solving exponential equations here:

brainly.com/question/28016999

5 0
1 year ago
Read 2 more answers
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