The length and width of the rug is 20 and 11 feet respectively
The given parameters;
dimension of the room = 19 ft by 28 ft
maximum area of rug she can afford = 220 ft²
For a uniform stripe of floor around the rug, then suppose the uniform excess length of the floor to removed from each dimension = y
(28-2x)(19-2x)=220
532-94x+4x^2=220
4x^2-94x+312=0
x=39/2,4
For x=39/2, dimensions are negative.
The uniform dimension of the floor to be covered by the maximum area of rug she can afford = (28 - 4×2) and (19 -2×4 ) = 20 and 11
Thus, the dimensions of the rug should be 20 feet and 11 feet
- The area of a rectangle is length times breadth.
- Area is the total squares cm occupied by a closed figure.
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He made 12*40=480 dollars in total. 0.0765*480=36.72 dollars were withheld.
Answer:
550
Step-by-step explanation:
1100/2=550
(can I get brainliest please)
Hello there.
To answer this question, we need to remember some properties about the vertex of quadratic functions.
Let 
. Its vertex can be found on the coordinates 
such that 
and 
, in which 
.
Using the coefficients given by the question, we get that:
Thus, we have:
So the statement is true, because the 
coordinate of the vertex of the function is equal to 
Answer:
(4,6)
Step-by-step explanation:
quadrant 1 always has positive coordinates so the only one with all positive coordinates is (4,6)
