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3 years ago

Lauren is making string bracelets with black and silver beads added in for decoration.

Mathematics

1 answer:

Agata [3.3K]3 years ago

6 0

Answer:

Step-by-step explanation:

Uh the black bean you can only put 3 in each 8 bracelet so yea that all

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when a pen is sold at a discount of 15%, there is a gain of Rs 10. but if it is sold at 25% discount, there is a loss of Rs 2. f

LenaWriter [7]

Answer:

Rs 120.

Step-by-step explanation:

10=0.85SP-CP; CP+10=0.85SP; SP=[CP+10]/0.85 Eq 1. Let SP= Selling Price and CP= Cost Price

-2 =0.75SP-CP; 0.75SP=C-2; SP=[CP-2]/0.75 Eq 2

[CP+10]/0.85=[CP-2]/0.75 : SP of Eq 1=SP of Eq 2

0.75[CP+10]=0.85[CP-2]

0.75CP+7.5=0.85CP-1.7

0.85CP-0.75CP=-1.7–7.5=9.2

0.10CP=9.2; CP=9.2/0.10

CP=Rs 92 Cost Price of pen

10=0.85SP-92; 0.85SP=92+10=102; SP=102/0.85=Rs 120 Marked Price of pen (answer)

From Eq2: -2=0.75SP-CP; 0.75SP=CP-2=92–2=90; SP=90/0.75=Rs120; -2=0.75(120)-CP; CP-2=0.75(120); CP-2=90; CP=90+2=Rs 92

Set CP of Eq 1=CP of Eq 2:

CP=0.85SP-10 from Eq 1; CP=0.75SP+2 from Eq 2;

0.85SP-10=0.75SP+2; 0.85SP-0.75SP=10+2=12

0.10SP=12; SP=12/0.10=Rs120 is the Marked Price(answer)

Normally, the Selling Price is the marked price. The seller will not disclose the Cost Price because it is the price when the item was acquired or procured, otherwise the buyer will ask for more discounts and based his buying price from the Cost Price if it is known. The calculated SP and CP satisfy both Eq 1 and Eq 2. Both Eq 1 and Eq 2 satisfy the given conditions of the problem above.

8 0

3 years ago

Find the unknow side of the right triangle 2. b=73.6 cm b= 19.0

shusha [124]

Assumed 73.6cm is the hypotenuse.

$a^{2} + b^{2} = c^{2}$
$19^{2} + b^{2} = 73.6^{2}$
$b^{2}$ = $73.6^{2} -19^{2}$
$b^{2}$ = $5055.96$
$b$ = $71.1$

Assumed 73.6cm is not the hypotenuse.
$a^{2} + b^{2} = c^{2}$
$19^{2} + 73.6^{2} = c^{2}$
$c^{2}$ = $73.6^{2} +19^{2}$
$c^{2}$ = $5777.96$
$c$ = $76.0$

7 0

3 years ago

The table represents a function.

Zarrin [17]

We have to complete the statement:

" The rate of change in the function y=x+4 is ______ the rate of change of the function represented in the table."

Let us consider the function represented in table.

The coordinates given in the table are:

(0,6) (2,8) (4,10) and (6,12)

Consider the first two coordinates (0,6) and (2,8)

$x_{1}=0 , y_{1}=6, x_{2}=2 , y_{2}=8$

Equation of line is given by $(y-y_{1})=m(x-x_{1})$

where 'm' is slope(rate of change) is given by the formula:

$m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

So, $m = \frac{8-6}{2-0}=1$

So, equation of line is :

(y-6)= 1 (x-0)

y-6=x

y=x+6

Comparing it with standard equation of line y=mx+c with slope 'm'.

So, we get m(Rate of change)=1.

Now,

We will find the rate of change(slope) in the function y=x+4

Comparing it with standard equation of line y=mx+c with slope 'm'.

So, we get m(Rate of change)=1.

So, " The rate of change in the function y=x+4 is equal to the rate of change of the function represented in the table.

7 0

4 years ago

On the first 6 exams of his chemistry class, William got an average score of 80. What does he need on the next exam to have an o

Pavlova-9 [17]

Answer:

He will need a 94 to get an 82 average

Step-by-step explanation:

82 x 7 =574

80 x 6 = 480

574-480 = 94

5 0

2 years ago

the ratio of boys to girls in Ms.Smith`s class is 3 to 4.If there are 12 boys,how many girls are there?

Anvisha [2.4K]

The question says boys/girls = 3/4 so if there are 12 boys in the class you can say:
3/4 = 12/?
and ? is the number of girls which is equal to:
? = 12*3/4 = 9
so if there are 12 boys in the class we will have 9 girls in the class :)))
i hope this is helpful
have a nice day

7 0

3 years ago