Let's say her speed was x miles/hour during the first 3 miles runThen, time = distance/speedt1 = 3/x eq1 In the next 4 miles run, her speed = x-1 miles/hourTime taken:t2 = 4/(x-1) eq2 Now, total time:t1 + t2 = 1 3/5 hourssubstitute t1 and t2 from eqs. 1 and 2 3/x + 4/(x-1) = 1 3/5=> 3/x + 4/(x-1) = 8/5
=> 3(x-1) + 4x = 8x(x-1)/5=> 35x - 15 = 8x2 - 8x=> 8x2 - 43x + 15 = 0=> (8x-3)*(x-5) = 0=> x = 3/8 or 5 miles/hourx can not be 3/8 miles/hour because in that case, the speed during 4 miles run would be 3/8-1 = negative numberi.e. speed during 3 miles segment = 5 miles/hourand speed during 4 miles segment = 5-1 = 4 miles/hour
Step-by-step explanation:
f(x) = (3/2)ˣ
g(x) = (2/3)ˣ
These are examples of exponential equations:
y = a bˣ
If b > 1, the equation is exponential growth.
If 0 < b < 1, the equation is exponential decay.
So f(x) is an example of exponential growth, and g(x) is an example of exponential decay.
Also, 2/3 is the inverse of 3/2, so:
g(x) = (3/2)^(-x)
So more specifically, f(x) and g(x) are reflections of each other across the y-axis.
Explanation: The base of the power in the original equation becomes the base of the log. So we have 
. Next, the exponent in the original equation goes on the other side of the equation and finally, the result in the original equation goes inside the log.
So we have 
= 
which is 2³ = 8 written in logarithmic form.
