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scZoUnD [109]
3 years ago
12

Here is an easy puzzle:

Mathematics
1 answer:
galina1969 [7]3 years ago
4 0
The answer is 
date
1                  2                 3          4             5                                         31
r1                r2               r3           r4          r5               .  .  .                  r31
1gm           2gms         3<span>gms     4gms    5gms        .   .  .                 31gms

r1+r2+ .... +r31= 31(31+1) /2=496gms  (31 rings)

he only made 5 rings

31 rings----------> 496 gms
5 rings ------------> ? = 5 x496  / 31=80 gms

</span><span> the weights of those 5 rings was 80 gms</span>
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Prove that 25^11−5^19 is divisible by 31.
SCORPION-xisa [38]

Answer:

Divisible by 3 is the answer

Step-by-step explanation:

First get everything to have the same base of 5

25^11 - 5^19

(5^2)^11 - 5^19

5^(2*11) - 5^19

5^22 - 5^19

Now factor out the GCF 5^19 to get

5^22 - 5^19

5^(19+3) - 5^(19+0)

5^19*5^3 - 5^19*5^0

5^19(5^3 - 5^0)

5^19(125 - 1)

5^19*(124)

At this point, we factor the 124 into 31*4 to end up with this full factorization: 5^19*31*4

Therefore, 25^11 - 5^19 is equivalent to 5^19*31*4

Since 31 is a factor of the original expression, this means the original expression is divisible by 31.

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3 years ago
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Step-by-step explanation:

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hope this helps, brainliest is always appreciated :3

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