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notsponge [240]
3 years ago
8

668 ÷ 35 show quotient as mixed number

Mathematics
2 answers:
liubo4ka [24]3 years ago
8 0
It is 1 31/35 mixed number
yulyashka [42]3 years ago
7 0
Quotient=19
remainder= 3
or
mixed number = 3/35 
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A car rental agency charges ​$33 per day to rent a car and ​$11.95 per day for a global positioning system​ (GPS). Customers are
harkovskaia [24]

(a) b = (33+11.95)d + 55.5

(b) The bill for a 5 day rental is $280.25

Step-by-step explanation:

Given,

Rent of car per day = $33

Rent of GPS per day = $11.95

Cost of gas = $3.70 per gallon

Cost of 15 gallons = 3.70*15 = $55.5 per tank

a) Write a function rule for the total bill b as a function of the days d the car is rented.

Let,

d be the number of days.

Total bill = (Rent of car per day + Rent of GPS per day )* Number of days + Cost of tank

b = (33+11.95)d + 55.5

b) What is the bill for a 5 day​ rental?

Putting d=5 in above function

b = (33+11.95)*5+55.5\\b=(44.95)*5+55.5\\b=224.75+55.5\\b=280.25

The bill for a 5 day rental is $280.25

Keywords: function, addition

Learn more about addition at:

  • brainly.com/question/9738996
  • brainly.com/question/9729310

#LearnwithBrainly

5 0
3 years ago
I think it’s b but I’m not sure
laila [671]
No, its D

Just look at the rounds mentioned and subtract the scores from higher round with lower round.

Look at A: round 2 score - round 1 score = -2?
-3 -1 = -4 change, not -2 change so it is wrong

Look at B: round 3 score - round 1 score =-1?
-2-1 =-3 change, not -1 change so it is wrong

Look at C: round 3 score - round 2 score =-1?
-2 -(-3) = 1 change, not -1 change so it is wrong

Look at D: round 3 score - round 1 score =-3?
-2-1 = -3 change, matches with -3 so it is correct.
3 0
2 years ago
What is the value of g(2)?
Svetlanka [38]

Answer:

i think its 2

D

according to me

8 0
3 years ago
Read 2 more answers
Find the derivative.
Aleksandr [31]

Answer:

Using either method, we obtain:  t^\frac{3}{8}

Step-by-step explanation:

a) By evaluating the integral:

 \frac{d}{dt} \int\limits^t_0 {\sqrt[8]{u^3} } \, du

The integral itself can be evaluated by writing the root and exponent of the variable u as:   \sqrt[8]{u^3} =u^{\frac{3}{8}

Then, an antiderivative of this is: \frac{8}{11} u^\frac{3+8}{8} =\frac{8}{11} u^\frac{11}{8}

which evaluated between the limits of integration gives:

\frac{8}{11} t^\frac{11}{8}-\frac{8}{11} 0^\frac{11}{8}=\frac{8}{11} t^\frac{11}{8}

and now the derivative of this expression with respect to "t" is:

\frac{d}{dt} (\frac{8}{11} t^\frac{11}{8})=\frac{8}{11}\,*\,\frac{11}{8}\,t^\frac{3}{8}=t^\frac{3}{8}

b) by differentiating the integral directly: We use Part 1 of the Fundamental Theorem of Calculus which states:

"If f is continuous on [a,b] then

g(x)=\int\limits^x_a {f(t)} \, dt

is continuous on [a,b], differentiable on (a,b) and  g'(x)=f(x)

Since this this function u^{\frac{3}{8} is continuous starting at zero, and differentiable on values larger than zero, then we can apply the theorem. That means:

\frac{d}{dt} \int\limits^t_0 {u^\frac{3}{8} } } \, du=t^\frac{3}{8}

5 0
3 years ago
Which statement correctly describes the relationship between the graph of f(x)=4x and the graph of g(x)=f(x)+3
Leya [2.2K]
<span>The graph of g(x) is the graph of f(x)translated 3 units up.</span>
3 0
3 years ago
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