Answer:
Step-by-step explanation:
From the figure attached,
Point B has been dilated to form point B'.
B(3, 1) → B'(6, 2)
           → B'[(2 × 3), (2 × 1)]
Since rule for the dilation of a point (x, y) by a factor of k is,
B(x, y) → B'(kx, ky)
By comparing the coordinates k = 2 is the scale factor by which the point B has been dilated about the origin.
Therefore, other vertices of the quadrilateral will be,
A(-2, 3) → A'(-4, 6)
C(1, -1) → C'(2, -2)
D(-3, -2) → D'(-6, -4) 
 
        
             
        
        
        
Answer.
Step-by-step explanation:
 
        
             
        
        
        
(3+11i)/(3+11i)=1
So that means you can multiply 6/(3+11i) by (3+11i)/(3+11i)
Then 6(3+11i)/1
= 18+66i
 
        
             
        
        
        
Answer:
12.
Step-by-step explanation:
 
        
             
        
        
        
Answer:
D. $31,337.27
Step-by-step explanation:
We have that the initial amount of the loan is $5500.
Miranda took the loan for 4 years. So, the total present value is $5500×4 = $22,000.
The rate of interest on the loan is 7.5% i.e. 0.075 and it was for the duration of 10 years.
Also, it is given that the loan was compounded annually.
We have the formula as,

i.e. ![PV=\frac{P\times [1-(1+\frac{r}{n})^{-t\times n}]}{\frac{r}{n}}](https://tex.z-dn.net/?f=PV%3D%5Cfrac%7BP%5Ctimes%20%5B1-%281%2B%5Cfrac%7Br%7D%7Bn%7D%29%5E%7B-t%5Ctimes%20n%7D%5D%7D%7B%5Cfrac%7Br%7D%7Bn%7D%7D)
Substituting the values, we get,
i.e. ![PV=\frac{P\times [1-(1+\frac{0.075}{12})^{-10\times 12}]}{\frac{0.075}{12}}](https://tex.z-dn.net/?f=PV%3D%5Cfrac%7BP%5Ctimes%20%5B1-%281%2B%5Cfrac%7B0.075%7D%7B12%7D%29%5E%7B-10%5Ctimes%2012%7D%5D%7D%7B%5Cfrac%7B0.075%7D%7B12%7D%7D)
i.e. ![22000=\frac{P\times [1-(1+0.00625)^{-120}]}{0.00625}](https://tex.z-dn.net/?f=22000%3D%5Cfrac%7BP%5Ctimes%20%5B1-%281%2B0.00625%29%5E%7B-120%7D%5D%7D%7B0.00625%7D)
i.e. ![22000=\frac{P\times [1-(1.00625)^{-120}]}{0.00625}](https://tex.z-dn.net/?f=22000%3D%5Cfrac%7BP%5Ctimes%20%5B1-%281.00625%29%5E%7B-120%7D%5D%7D%7B0.00625%7D)
i.e. ![22000=\frac{P\times [1-0.4735]}{0.00625}](https://tex.z-dn.net/?f=22000%3D%5Cfrac%7BP%5Ctimes%20%5B1-0.4735%5D%7D%7B0.00625%7D)
i.e. 
i.e. 
i.e. 
i.e. 
Thus, the total lifetime cost to pay of the loans compounded annually  = 261.16 × 120 = $31,339.2
Hence, the total cost close to the answer is $31,337.27