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3 years ago

What is the simplified form of this expression, written in scientific notation? (3.276×105)×400,000÷(3.9×106)

Mathematics

2 answers:

melomori [17]3 years ago

5 0

Answer:

(343.98)x400,000/(413.4)

137,592,000/413.4

332,830.188679

Step-by-step explanation:

vlada-n [284]3 years ago

3 0

(343.98)x400,000/(413.4)
137,592,000/413.4
332,830.188679

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Line ET is tangent to circle A and T, and the measure of arc TG is 46 degrees. What is the measure of Angle GET

kogti [31]

Answer:

$m\angle GET=67^o$

Step-by-step explanation:

The picture of the question in the attached figure

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3 years ago

Put the differential equation 9ty+ety′=yt2+81 into the form y′+p(t)y=g(t) and find p(t) and g(t). p(t)= help (formulas) g(t)= he

alexgriva [62]

Answer:

$p(t) = \frac{9t^{3} + 729t - 1}{e^{t}(t^{2} + 81) }$

g(t) = 0

And

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Step-by-step explanation:

Given that,

The differential equation is -

$9ty + e^{t}y' = \frac{y}{t^{2} + 81 }$

$e^{t}y' + (9t - \frac{1}{t^{2} + 81 } )y = 0\\e^{t}y' + (\frac{9t(t^{2} + 81 ) - 1}{t^{2} + 81 } )y = 0\\e^{t}y' + (\frac{9t^{3} + 729t - 1}{t^{2} + 81 } )y = 0\\y' + [\frac{9t^{3} + 729t - 1}{e^{t}(t^{2} + 81) } ]y = 0$

By comparing with y′+p(t)y=g(t), we get

$p(t) = \frac{9t^{3} + 729t - 1}{e^{t}(t^{2} + 81) }$

g(t) = 0

And

The differential equation $9ty + e^{t}y' = \frac{y}{t^{2} + 81 }$ is linear and homogeneous.

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3 years ago