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sp2606 [1]
4 years ago
7

What is the volume of a sphere with an 18 inch diameter ?

Mathematics
2 answers:
Marianna [84]4 years ago
8 0
<h2>Volume = 3,052.08 in³</h2><h2></h2><h2>Work is attached in the image provided.</h2>

photoshop1234 [79]4 years ago
3 0
18 inch diameter = 9 inch radius
Sphere Volume   = <span>  4/3 • <span>π <span>• r³
</span></span></span><span>Sphere Volume   = <span>  4/3 * PI * 9^3
</span></span><span>Sphere Volume   = <span>  4/3 * PI * 729
</span></span><span><span>Sphere Volume   =   </span>3,053.628 </span>




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4 years ago
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What is the cost of constructing a fence 6 feet, 6 inches, high around a lot measuring 90 feet by 175 feet, if the cost of erect
boyakko [2]

Answer:

The total cost is  $3,504.63

Step-by-step explanation:

Length of fence = 90 feet

Breadth of fence = 175 feet

Height of fence = 6 feet, 6 inches

1 inch = 0.0833333 feet

6 inches = 6*0.0833333 =0.4999998  feet

So, Height of fence = 6 feet + 0.49 feet =6.49 feet ≈ 6.5 feet

Perimeter = 2(Length \times breadth)=2(90 +175) = 530 feet

Cost of erecting the fence is $1.25 per linear foot

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Total surface area = 2(length +breadth) Height =530 \times 6.5=3445ft^2

The cost of materials is $0.825 per square foot of fence

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3 years ago
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r-ruslan [8.4K]
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The other sides that are marked as congruent are the heights of each triangle.

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erik [133]

9514 1404 393

Answer:

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  • loading: $75 per hour
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Step-by-step explanation:

We can let P and L represent the hourly costs of packing and loading, respectively. The two estimates can be represented by the equations ...

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The LCM of the coefficients of L is LCM(5, 3) = 15.

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Each LCM is the product of the numbers, divided by their greatest common factor. For 4 and 6, the product is 24, and both even numbers have a factor of 2, so the LCM of 4 and 6 is 24/2 = 12. The numbers 3 and 5 have no common factors, so the LCM is simply their product.

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The LCM is useful if you're going to solve the equations by "elimination". Here, the LCM of 12 means we can eliminate P by making its coefficient be 12 in both equations. Multiplying the first equation by 2, we can subtract 3 times the second equation to eliminate P:

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