X^5 (X to the fifth power) - 4 (x^5 - 4)
H = Heads, T = tails
1st Coin 2nd Coin Final Outcome, ÷ 4 possible outcomes
H (H,H) 1/4, or 25%
H
T (H,T) 1/4, or 25%
H (T,H) 1/4, or 25%
T
T (T,T) 1/4, or 25%
If order does not matter:
T,T: 25%
TH or HT: 50%
HH: 25%
1. Take an arbitrary point that lies on the first line y=3x+10. Let x=0, then y=10 and point has coordinates (0,10).
2. Use formula
to find the distance from point
to the line Ax+By+C=0.
The second line has equation y=3x-20, that is 3x-y-20=0. By the previous formula the distance from the point (0,10) to the line 3x-y-20=0 is:
.
3. Since lines y=3x+10 and y=3x-20 are parallel, then the distance between these lines are the same as the distance from an arbitrary point from the first line to the second line.
Answer:
.
Over this 10-minute interval, the car's average acceleration is

The MVT says that at some point during this 10-minute interval, the car must have had an acceleration of 60 mi/h^2.
Answer:
Option 3)............... I guess so