If you would like to solve for f(g(x)) when x = 1, you can do this using the following steps:
<span>f(x) = x^2 - 3x + 6
g(x) = x - 3/2
f(g(x)) = f(</span>x - 3/2) = (x - 3/2)^2 - 3 * (x - 3/2) + 6
x = 1
f(g(1)) = f(1 - 3/2) = f(-1/2) = (-1/2)^2 - 3 * (-1/2) + 6 = 1/4 + 3/2 + 6 = 1/4 + 6/4 + 24/4 = 31/4 = 7 3/4
The correct result would be 7 3/4. add me as a friend
To solve this we are going to use the future value of annuity due formula:
![FV=(1+ \frac{r}{n} )*P[ \frac{(1+ \frac{r}{n} )^{kt} -1}{ \frac{r}{n} } ]](https://tex.z-dn.net/?f=FV%3D%281%2B%20%5Cfrac%7Br%7D%7Bn%7D%20%29%2AP%5B%20%5Cfrac%7B%281%2B%20%5Cfrac%7Br%7D%7Bn%7D%20%29%5E%7Bkt%7D%20-1%7D%7B%20%5Cfrac%7Br%7D%7Bn%7D%20%7D%20%5D)
where

is the future value

is the periodic payment

is the interest rate in decimal form

is the number of times the interest is compounded per year

is the number of payments per year

is the number of years
We know for our problem that

and

. To convert the interest rate to decimal for, we are going to divide the rate by 100%:


Since the payment is made quarterly, it is made 4 times per year; therefore,

.
Since the type of the annuity is due, payments are made at the beginning of each period, and we know that we have 4 periods, so

.
Lets replace those values in our formula:
![FV=(1+ \frac{r}{n} )*P[ \frac{(1+ \frac{r}{n} )^{kt} -1}{ \frac{r}{n} } ]](https://tex.z-dn.net/?f=FV%3D%281%2B%20%5Cfrac%7Br%7D%7Bn%7D%20%29%2AP%5B%20%5Cfrac%7B%281%2B%20%5Cfrac%7Br%7D%7Bn%7D%20%29%5E%7Bkt%7D%20-1%7D%7B%20%5Cfrac%7Br%7D%7Bn%7D%20%7D%20%5D)
![FV=(1+ \frac{0.1}{4} )*295[ \frac{(1+ \frac{0.1}{4} )^{(4)(6)} -1}{ \frac{0.1}{4} } ]](https://tex.z-dn.net/?f=FV%3D%281%2B%20%5Cfrac%7B0.1%7D%7B4%7D%20%29%2A295%5B%20%5Cfrac%7B%281%2B%20%5Cfrac%7B0.1%7D%7B4%7D%20%29%5E%7B%284%29%286%29%7D%20-1%7D%7B%20%5Cfrac%7B0.1%7D%7B4%7D%20%7D%20%20%5D%20)
We can conclude that the amount of the annuity after 10 years is $9,781.54
Answer:
0.58
Step-by-step explanation:
because they are the Decimals
X=14
y=3x^2+17
y=3(14)^2+17
y=3•196+17
y=588+17
y=605
the real solutions for the equation
are -

Step-by-step explanation:
= 
= 0
We can write 64 as
+
= 0
using the identity (
)
we get,
= 
=
....................(1)
solving the quadratic equation ,
=0
solutions of this quadratic equation can be obtained by

let use y for factors




<u />
..................(2)
from the equation 1 we have,

which gives solution
and from equation 2 we got 
so the real solutions for the equation
are -
