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Lelu [443]
3 years ago
5

What is the midpoint of the segment shown below

Mathematics
2 answers:
grigory [225]3 years ago
5 0

Answer:  The midpoint of the given line segment is (5, 1).

Step-by-step explanation:  We are given to find the mid-point of the segment shown in the figure.

From the figure, we can see a line segment with co-ordinates of the endpoints (3, 4) and (7, -2).

We know that

The midpoint of a line segment with co-ordinates of the endpoints (a, b) and (c, d) is given by

M=\left(\dfrac{a+c}{2},\dfrac{b+d}{2}\right).

Therefore, the co-ordinates of the midpoint of the given line segment will be

M=\left(\dfrac{3+7}{2},\dfrac{4+(-2)}{2}\right)=\left(\dfrac{10}{2},\dfrac{2}{2}\right)=(5,1).

Thus, the midpoint of the given line segment is (5, 1).

asambeis [7]3 years ago
3 0
Midpoint = ( \frac{X2+X1}{2} ,  \frac{Y2+Y1}{2} )

Plug in:

( \frac{3+7}{2} ,  \frac{4+(-2)}{2} )

Equals:

( \frac{10}{2} ,  \frac{2}{2})

Your answer is then:

(5, 1), your midpoint. 
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2 years ago
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laila [671]

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The proof is rigourous and well written, so we discard the second answer.

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A meaningful proof by contradiction depends strongly on the assumption that the statement to prove is false. In this argument, we only this assumption once, thus it is innecessary. Other proofs by contradiction, like the proof of "The square root of 2 is irrational" or Euclid's proof of the infinitude of primes, develop a longer argument based on the new assumption, but this proof doesn't.

To rewrite this without the superfluous framework, erase the parts "Suppose that the statement is false" and "The fact that the statement is true contradicts the assumption that the statement is false. Thus, the assumption that the statement was false must have been false. Thus, the statement is true."

7 0
3 years ago
Particle 1 of charge q1 �� ��5.00q and particle 2 of charge q2 �� ��2.00q are fixed to an x axis. (a) as a multiple of distance
Naya [18.7K]

<span>Assuming that the particle is the 3rd particle, we know that it’s location must be beyond q2; it cannot be between q1 and q2 since both fields point the similar way in the between region (due to attraction). Choosing an arbitrary value of 1 for L, we get </span>

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k q1 / d^2 = - k q2 / (d-1)^2 </span>

Rearranging to calculate for d:

<span> (d-1)^2/d^2 = -q2/q1 = 0.4 </span><span>
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d = 0.612574113277207 </span>

<span>
We pick the value that is > q2 hence,</span>

d = 2.72075922005613*L

<span>d = 2.72*L</span>

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