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Lelu [443]
4 years ago
5

What is the midpoint of the segment shown below

Mathematics
2 answers:
grigory [225]4 years ago
5 0

Answer:  The midpoint of the given line segment is (5, 1).

Step-by-step explanation:  We are given to find the mid-point of the segment shown in the figure.

From the figure, we can see a line segment with co-ordinates of the endpoints (3, 4) and (7, -2).

We know that

The midpoint of a line segment with co-ordinates of the endpoints (a, b) and (c, d) is given by

M=\left(\dfrac{a+c}{2},\dfrac{b+d}{2}\right).

Therefore, the co-ordinates of the midpoint of the given line segment will be

M=\left(\dfrac{3+7}{2},\dfrac{4+(-2)}{2}\right)=\left(\dfrac{10}{2},\dfrac{2}{2}\right)=(5,1).

Thus, the midpoint of the given line segment is (5, 1).

asambeis [7]4 years ago
3 0
Midpoint = ( \frac{X2+X1}{2} ,  \frac{Y2+Y1}{2} )

Plug in:

( \frac{3+7}{2} ,  \frac{4+(-2)}{2} )

Equals:

( \frac{10}{2} ,  \frac{2}{2})

Your answer is then:

(5, 1), your midpoint. 
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Simplification<br> (a-b)²=a²+2ab-b²
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<h2> ANSWER:</h2>

<em>I wonder if you have your equation wrong, because(a−b)2=(a−b)(a−b)=a2−ab−ba+b2=a2–2ab+b2</em>

<em> </em>

<em> Your equation, on the other hand, is (a+b)2 and that is not equal to (a−b)2 except when ab=0, i.e. when either a or b equals 0, and that is not what we normally mean by “prove”. Prove would imply “for all values of a and b”, which is not the case in the form you have your equation,</em>

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<em><u>then </u></em><em><u>plz </u></em><em><u>like </u></em><em><u>and </u></em><em><u>follow </u></em><em><u>me.</u></em><em><u>. </u></em><em><u>♥</u></em>

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3 years ago
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irina [24]

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The accurate height is measured by Doctor, as he have more accurate measurement system.

5 0
3 years ago
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