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4 years ago

13

The weatherman predicted that the temperature would be within 3° of 52°F.( express each statement using an inequality involving

absolute value)

1 answer:

jekas [21]4 years ago

5 0

49 $\leq$ x $\geq$ 55

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4 years ago

Round 3.85 to the nearest one

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3 years ago

the circumference of a circle is blank. a)the distance around the circle b)the length of a radius c)2pie d)the length of the dia

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4 years ago

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3 years ago

Differentiating Functions of Other Bases In Exercise, find the derivative of the function.

aniked [119]

Answer:

$\dfrac{dy}{dx} = \frac{2x-3}{\ln 16(x^2 - 3x)}$

Step-by-step explanation:

We are given the following in the question:

$y = \ln {16}(x^2 - 3x)$

We have to find the derivative of the given expression.

$y = \ln 16(x^2 - 3x)\\\text{Using the log propert}\\\\\log_a b = \dfrac{\log b}{\log a}\\\\dfrac{d(x^n)}{dx} = nx^{n-1}\\\\\dfrac{d(\log x)}{dx} = \dfrac{1}{x}\\\\\text{\bold{Differentiating we get}}\\\\\displaystyle\frac{dy}{dx} = \frac{d(\ln 16(x^2-3x))}{dx}\\\\= \frac{1}{16(x^2-3x)})\frac{d(x^2-3x)}{dx}\\\\=\frac{1}{\log 16(x^2-3x)}(2x - 3)\\\\= \frac{2x-3}{\ln 16(x^2 - 3x)}$

$\dfrac{dy}{dx} = \frac{2x-3}{\ln 16(x^2 - 3x)}$

7 0

4 years ago