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3 years ago

Please help this hurts

Mathematics

1 answer:

Svetllana [295]3 years ago

3 0

Answer:

6x - 11y = -13 is the answer.

Step-by-step explanation:

Let's plug in the points to see what sticks.

Start with (-4, -1)

1) 11x - 6y = 11(-4) - 6(-1) = -44 + 6 = -38 $\neq$ 13

2) 6x - 11y = 6(-4) - 11(-1) = -24 + 11 = -13

3) 6x - 7y = 6(-4) - 7(-1) = -24 + 7 = -17 $\neq$ 17

4) 6x - 11y = 6(-4) - 11(-1) = -24 + 11 = -13 $\neq$ 13

The only one that fits is #2. Let's try the other point to be sure.

2) 6x - 11y = 6(1.5) - 11(2) = 9 - 22 = -13

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The resulting equation after simplyfing the given equation is 3x^2 + 20x + 12 = 0 and whoose solutions are x = -2/3 or x = -6.

According to the given question.

We have an equation

$\frac{x^{2}-x-6 }{x^{2} } = \frac{x-6}{2x} +\frac{2x+12}{x}$

So, to find the resulting equation of the above equation we need to simplify.

First we will take LCD

$\frac{x^{2} -x - 6 }{x^{2} } = \frac{x -6+2(2x + 12)}{2x}$

$\implies \frac{x^{2}-x-6 }{x^{2} } =\frac{x-6+4x+24}{2x}$

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Multiply both the sides by x.

$\frac{x^{2}-x-6 }{x} = \frac{5x+18}{2}$

Again multiply both the sides by x

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$\implies 5x^{2} -2x^{2} +18x +2x +12 = 0$

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Factorize the above equation

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⇒(3x + 2)(x+6) = 0

⇒ x = -2/3 or x = -6

Hence, the resulting equation after simplyfing the given equation is 3x^2 + 20x + 12 = 0 and whoose solutions are x = -2/3 or x = -6.

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