bearing in mind that, on the III Quadrant, sine as well as cosine are both negative, and that hypotenuse is never negative, so, if the sine is -4/5, the negative number must be the numerator, so sin(x) = (-4)/5.
![\bf sin(x)=\cfrac{\stackrel{opposite}{-4}}{\stackrel{hypotenuse}{5}}\impliedby \textit{let's find the \underline{adjacent}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{5^2-(-4)^2}=a\implies \pm\sqrt{9}=a\implies \pm 3=a \\\\\\ \stackrel{III~Quadrant}{-3=a}~\hfill cos(x)=\cfrac{\stackrel{adjacent}{-3}}{\stackrel{hypotenuse}{5}} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20sin%28x%29%3D%5Ccfrac%7B%5Cstackrel%7Bopposite%7D%7B-4%7D%7D%7B%5Cstackrel%7Bhypotenuse%7D%7B5%7D%7D%5Cimpliedby%20%5Ctextit%7Blet%27s%20find%20the%20%5Cunderline%7Badjacent%7D%7D%20%5C%5C%5C%5C%5C%5C%20%5Ctextit%7Busing%20the%20pythagorean%20theorem%7D%20%5C%5C%5C%5C%20c%5E2%3Da%5E2%2Bb%5E2%5Cimplies%20%5Csqrt%7Bc%5E2-b%5E2%7D%3Da%20%5Cqquad%20%5Cbegin%7Bcases%7D%20c%3Dhypotenuse%5C%5C%20a%3Dadjacent%5C%5C%20b%3Dopposite%5C%5C%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20%5Cpm%5Csqrt%7B5%5E2-%28-4%29%5E2%7D%3Da%5Cimplies%20%5Cpm%5Csqrt%7B9%7D%3Da%5Cimplies%20%5Cpm%203%3Da%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7BIII~Quadrant%7D%7B-3%3Da%7D~%5Chfill%20cos%28x%29%3D%5Ccfrac%7B%5Cstackrel%7Badjacent%7D%7B-3%7D%7D%7B%5Cstackrel%7Bhypotenuse%7D%7B5%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![\bf tan\left(\cfrac{\theta}{2}\right)= \begin{cases} \pm \sqrt{\cfrac{1-cos(\theta)}{1+cos(\theta)}} \\\\ \cfrac{sin(\theta)}{1+cos(\theta)}\qquad \leftarrow \textit{let's use this one} \\\\ \cfrac{1-cos(\theta)}{sin(\theta)} \end{cases} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20tan%5Cleft%28%5Ccfrac%7B%5Ctheta%7D%7B2%7D%5Cright%29%3D%20%5Cbegin%7Bcases%7D%20%5Cpm%20%5Csqrt%7B%5Ccfrac%7B1-cos%28%5Ctheta%29%7D%7B1%2Bcos%28%5Ctheta%29%7D%7D%20%5C%5C%5C%5C%20%5Ccfrac%7Bsin%28%5Ctheta%29%7D%7B1%2Bcos%28%5Ctheta%29%7D%5Cqquad%20%5Cleftarrow%20%5Ctextit%7Blet%27s%20use%20this%20one%7D%20%5C%5C%5C%5C%20%5Ccfrac%7B1-cos%28%5Ctheta%29%7D%7Bsin%28%5Ctheta%29%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
Answer:
Exploratory Research
Step-by-step explanation:
Exploratory Research is a preliminary research method that implement various research methods to increase the understanding of a concept, to clarify the exact nature of the problem to be solved, or to identify important variables to be studied.
For example, if i'm making analysis on the quality of customer care service at particular firm, let's say MTN GlobalCom. Exploratory research method will be greatly advantageous if being used for such analysis because of the ways it is used for data collection and selection of variables. It will assist me to determine the problems the customer care service are facing with their clients and how to tackle them.
Answer:
D.
Step-by-step explanation:
a² -b²= (a-b)(a+b)
100x²-49y²= (10x-7y)(10x+7y)
Well, we can really show our work because their is no work to be done. Question 7 is a right angle because it is exactly 90 degrees. So since you now know what a right angle is, you can probably guess Question 8 a would be either 3 o'clock or 9 o'clock. For question 8b , he first one, and acute angle is an angle where it is below 90 degrees. So an example of an acute time is 3:05. An obtuse angle is an angle above 90 degrees. So an obtuse time would be (for example) 3:55. Hope this helped.
Answer: Ava doesn’t have sufficient evidence to reject the fast-food chains claim.
Step-by-step explanation: I got it right on the quiz lol
