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Ksenya-84 [330]
3 years ago
8

Calvin bought 20 pencils at $0.45 each. How much change did he get from a $10 bill?

Mathematics
2 answers:
Yanka [14]3 years ago
7 0
He would have one dollar left
Oxana [17]3 years ago
6 0
20 x 0.45 = 9
10-9=1
Calvin got $1 in change
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43cm =how many meters
Katena32 [7]
Answer:  43 cm = 0.43 meters   
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4 years ago
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The amount y (in grams) of the radioactive isotope fermium-253 remaining after t hours is y=a(0.5)t/72, where a is the initial a
almond37 [142]

Answer:

Per hour decay of the isotope is 0.96%.

Step-by-step explanation:

Amount of radioactive element remaining after t hours is represented by

y=a(0.5)^{\frac{t}{72}}

where a = initial amount

t = duration of decay (in hours)

Amount remaining after 1 hour will be,

y=a(0.5)^{\frac{1}{72} }

y = 0.9904a

So amount of decay in one hour = a - 0.9904a

                                                      = 0.0096a gms

Percentage decay every hour = \frac{\text{Amount of decay}}{\text{Initial amount}}\times 100

                                                  = \frac{0.0096a}{a}\times 100

                                                  = 0.958 %

                                                  ≈ 0.96 %

Therefore, per hour decay of the radioactive isotope is 0.96%.

7 0
4 years ago
Help?
Gre4nikov [31]
A = P(1 + r)^t is the interest formula
A = 1000(1 + .02)^t
A = 1000(1.02)^t
I'm not sure which of your two answers A or C have the t raised to a power but you need to choose the one with the t raised to a power.
6 0
3 years ago
Find the distance from the point (1,4) to the line y = 1/3x - 3
Troyanec [42]

Answer:

Step-by-step explanation:

If I'm not mistaken, and I very well could be, this is a calculus problem(?). In order to find the distance without calculus you'd need a point on the given line to use to find the distance in the distance formula. But you don't have a point on the given line, so we can find the shortest distance between the point (1, 4) and the given line using the derivative of the polynomial formed when using the distance formula.

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} and we have the x and y for x2 (or x1...it doesn't matter which you choose to fill in):

d=\sqrt{(1-x)^2+(4-y)^2}

but what we find is that we have too many unknowns here, namely, the distance, the x coordinate, and the y coordinate. So we can replace the y coordinate with what y is equal to in terms of the linear equation:

d=\sqrt{(1-x)^2+(4-\frac{1}{3}x-3)^2 } and simplify:

d=\sqrt{(1-x)^2+(7-\frac{1}{3}x)^2 }

. No we'll expand each binomial by squaring:

d=\sqrt{(1-2x+x^2)+(49-\frac{14}{3}x+\frac{1}{9}x^2)  }

.  Combining like terms gives us

d=\sqrt{\frac{10}{9}x^2-\frac{20}{3}x+50  }

The distance between the point (1, 4) and the given line will be at a minimum when the polynomial above is at a minimum. We find the value of x for which the polynomial is at a minimum by finding its derivative, setting the derivative equal to 0, and then solving for x. The derivative of the polynomial is

\frac{20}{9}x-\frac{20}{3}

Setting equal to 0 and getting rid of the denominators gives us

20x - 60 = 0

Solving for x gives us

20x = 60 and x = 3.

That's the value of x that gives us the shortest distance between (1, 4) and the line y = 1/3x - 3. Sub into the distance formula that x value to find the distance:

d=\sqrt{(\frac{10}{9})(3)^2-(\frac{20}{3})(3)+50   }

which simplifies down, finally, to

x ≈ 6.325 units

8 0
3 years ago
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lara31 [8.8K]
1/16.  that is the value that has the most x's on the graph.
8 0
3 years ago
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